The mass of the block is 920 kg.
The angle of inclination of the slope with respect to the plane is 30 degree.
The initial speed of the block [u] =50 cm/s
=50×0.01 m/s
=0.5 m/s
The block is once pushed and it moves downward on the slope. The distance of the block from the bottom is 2.3 m .
Hence the distance travelled by the block [s]=2.3 m
We are asked to calculate the final velocity of the block when it touches the ground.
First we have to calculate the acceleration of the block.
Resolving g into horizontal and vertical component we get,
![[1] gsin\theta\ is\ along\ the\ slope\ and\ downward](https://tex.z-dn.net/?f=%5B1%5D%20gsin%5Ctheta%5C%20is%5C%20along%5C%20the%5C%20slope%5C%20and%5C%20downward)
![[2] gcos\theta\ is\ along\ the\ normal\ drawn\ to\ the\ block](https://tex.z-dn.net/?f=%5B2%5D%20gcos%5Ctheta%5C%20is%5C%20along%5C%20the%5C%20normal%5C%20drawn%5C%20to%5C%20the%5C%20block)
Now putting the equation of kinematics we get-
Here v is called final velocity and a is the acceleration.
![=[0.5]^2+2*gsin\theta *2.3](https://tex.z-dn.net/?f=%3D%5B0.5%5D%5E2%2B2%2Agsin%5Ctheta%20%2A2.3)
![=0.25+[2*9.8*0.5*2.3]](https://tex.z-dn.net/?f=%3D0.25%2B%5B2%2A9.8%2A0.5%2A2.3%5D)
[sin30=0.5]
[ans]
Answer: The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet.
Explanation:
Brainliest
The Earth's atmosphere is kept close to Earth by gravity. Just as the Earth's gravity keeps you firmly on the ground, it also acts on the gases of the Earth's atmosphere, holding it in place and allowing us to breathe.
Since g is constant, the force the escaping gas exerts on the rocket will be 10.4 N
<h3>
What is Escape Velocity ?</h3>
This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.
Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.
To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters
- Mass (m) of the rocket 0.25 Kg
- Initial velocity u = 15 m/s
- Final Velocity v = 40 m/s
- Gravitational field intensity g = 9.8N/kg
The force the gas exerts of the rocket = The force on the rocket
The rate change in momentum of the rocket = force applied
F = ma
F = m(v - u)/t
F = 0.25 x (40 - 15)/0.6
F = 0.25 x 41.667
F = 10.42 N
Since g is constant, the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.
Learn more about Escape Velocity here: brainly.com/question/13726115
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Answer:
1.88 m/s
Explanation:
from elastic collision
KE before collision = KE after collision
