Answer:
1. Which statement correctly describes the classification of chemical reactions into different categories?
-Not all reactions fit into a category, and some reactions can fit into more than one category.
2. In a synthesis reaction, two atoms of sodium (Na) combine with one molecule of chlorine gas (Cl2) to produce sodium chloride (NaCl). How many molecules of sodium chloride are produced?
-Two
3. In the decomposition of water, why is twice as much hydrogen as oxygen formed?
- There are two atoms of hydrogen and one atom of oxygen in a water molecule.
4. Which component is transferred between substances in an oxygen-reduction reaction?
-Electrons
5. In a chemical reaction, substance A transfers electrons to substance B. Which statement is correct?
-Substance B is reduced and acts as the oxidizing agent.
Answer:
E) are electrically attracted to each other
Explanation:
Water molecule is polar because there is a difference in electronegativity values between hydrogen and oxygen. The hydrogen side of the molecule has a slight positive charge and the oxygen side is slightly negatively.
Positively and negatively charged ends cause water molecules to attract one another and for this reason water shows the properties mentioned in the question: cohesion, high specific heat, and high heat of vaporization.
Because when the orange frog eats the red fly the dye that make the fly red turns the frog red very slowly
Answer:
Explanation:
The formula of the reaction:
KClO₂ → KCl + O₂
To assign oxidation numbers, we have to obey some rules:
- Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
- The charge on simple ions signifies their oxidation number.
- The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.
The oxidation number of K in KClO₂:
K + (-1) + 2(-2) = 0
K-5 = 0
K = +5
The oxidation number of K in KCl:
K + (-1) = 0
K = +1
The oxidation number Cl in KClO₂ is -1
For Cl in KCl, the oxidation number is -1
For O in KClO₂, the oxidation number is (2 x -2) = -4
For O in O₂, the oxidation number is 0
K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.
O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.
Explanation:
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