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fredd [130]
3 years ago
14

A comfortable room temperature is 20 celsius. What is the temperature in degrees fahrenheit

Physics
1 answer:
Agata [3.3K]3 years ago
3 0
The formula for Celsius to Fahrenheit is T(°F)<span> = </span>T(°C)<span> × 1.8 + 32

Your answer would be 68 degrees Fahrenheit</span>
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-Which of the following wires will have the least resistance?
scoray [572]
The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps
7 0
3 years ago
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In order to get the most accurate mass measurement, you must __(blank)__.
pshichka [43]

Answer:

c

Explanation:

electronic balance must always be at zero to prevent errors in measured value

4 0
3 years ago
The radius of curvature of a loop-the-loop for a roller coaster is 12.4 m. at the top of the loop (with the car inside the loop)
Ksenya-84 [330]
<span>14.79 m/s At the top of the loop, there's 2 opposing forces. The centripetal force that's attempting to push the roller coaster away and the gravitational attraction. These 2 forces are in opposite directions and their sum is 0.80 mg where m = mass and g = gravitational attraction. So let's calculate the amount of centripetal force we need. 0.80 = F - 1.00 1.80 = F So we need to have a centripetal force that's 1.8 times the local gravitational attraction which is 9.8 m/s^2. So 1.8 * 9.8 m/s^2 = 17.64 m/s^2 The formula for centripetal force is F = mv^2/r where F = force m = mass v = velocity r = radius We can eliminate mass from the equation since the same mass is being affected by both the centripetal force and gravity. So: F = v^2/r 17.64 m/s^2 = v^2/12.4 m 218.736 m^2/s^2 = v^2 14.78972616 m/s = v So the velocity at the top of the loop (rounded to 2 decimal places) is 14.79 m/s.</span>
8 0
4 years ago
How much force can a 2.5 kg sledge hammer excerpt on a nail if you can swing the hammer at 20 m/s and the hammer contacts the na
AleksAgata [21]

Answer:

625 N

Explanation:

The impulse given to the nail is equal to the change in momentum of the hammer:

I=F \Delta t=m \Delta v

where

F is the force exerted by the hammer

\Delta t=0.08 s is the time of contact

m=2.5 kg is the mass

\Delta v=20 m/s is the change in velocity of the hammer

Substituting the data and re-arranging the equation, we can find the force:

F=\frac{m \Delta v}{\Delta t}=\frac{(2.5 kg)(20 m/s)}{0.08 s}=625 N

4 0
4 years ago
Manuel is holding a 5kg box. How much force is the box exerting on him?In what direction
soldi70 [24.7K]
The force the box is exerting on Manuel is the weight of the box, downward:
W=mg=(5 kg)(9.81 m/s^2)=49.05 N
and this force is perfectly balanced by the constraint reaction applied by Manuel's hand, pushing upward.
3 0
4 years ago
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