4 years ago

When the charges in the rod are in equilibrium, what is the magnitude of the electric field within the rod?

Physics

1 answer:

Anarel [89]4 years ago

3 0

Answer: If we have equilibrium, the magnitude must be zero.

Explanation:

If the charges are in equilibrium, this means that the total charge is equal to zero.

And as the charges must be homogeneously distributed in the rod, we can conclude that the electric field within the rod must be zero, so the magnitude of the electric field must be zero

You might be interested in

What element is produced when the isotope bismuth-213 emits a beta particle

rusak2 [61]

Answer:

Explanation:

4 0

3 years ago

What are the magnitude and direction of electric field at the center of square?

Kobotan [32]

Answer:

hello the diagram related to this question is missing attached below is the missing diagram

Answer :

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

Explanation:

The magnitude of the electric field = 4KQ / L^2

direction = 45° east to south

6 0

3 years ago

What is lenz law?<br>What is galvanometer?

yulyashka [42]

Answer:

Lenz's law, in electromagnetism, statement that an induced electric current flows in a direction such that the current opposes the change that induced it. This law was deduced in 1834 by the Russian physicist Heinrich Friedrich Emil Lenz (1804–65).

6 0

2 years ago

Explain in your own words how volume is measured.

pav-90 [236]

Answer:

volume measured by pid^3 over 6 i think

Explanation:

7 0

3 years ago

Read 2 more answers

A 25.0 kg pickle is accelerated from rest through a distance of 6.0m in 4.0s across a level floor . If the friction force betwee

SIZIF [17.4K]

Add the KE increase and the work done against friction.

The final velocity is twice the average, or 3.0 m/s
The final KE is (1/2)*25*3^2 = 112.5 J

The friction work done is 6*3.8 = 22.8 J
hope this is correct

8 0

4 years ago