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2 years ago

a contractor is mixing concrete and mixed 3 parts concrete and 9 parts water. How much water is needed for 12 parts concrete?

Mathematics

1 answer:

weeeeeb [17]2 years ago

5 0

Answer:

36 parts water

Step-by-step explanation:

3/9 = 1/3 = for every 1 part concrete, it's 3 parts water.

12/x = 1/3; x = 36

so, 12 x 3 = 36

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Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

If possible, find AB. & State the dimension of the result.

Nikitich [7]

Answer:

Step-by-step explanation:

$A=\begin{bmatrix}0 &0 &5 \\ 0 &0 &-3 \\ 0 &0 &3 \end{bmatrix}$

$B=\begin{bmatrix}8 &-12 &5 \\ 7 &19 &5 \\ 0 &0 &0 \end{bmatrix}$

A.B = A × B

$A.B=\begin{bmatrix}0 &0 &0 \\ 0 &0 &0 \\ 0 &0 &0 \end{bmatrix}$

Dimension of the resultant matrix is (3 × 3)

3 0

2 years ago

A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?

Hatshy [7]

<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

Solution:

The volume of triangular prism is given as:

$v = base\ area \times height$

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

Substituting the values we get,

$428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2$

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0

3 years ago

3 Simplify the expression: 5! 2:3! 4. Simplify the expression:

vredina [299]

Answer:

Step-by-step explanation:

$5! 2:3! 4 \\ \\ = \frac{5! \: .2}{3! \: . 4} \\ \\ = \frac{5.4. \cancel{3!} \: . 2}{\cancel{3!} \: .4} \\ \\ = \frac{40}{4} \\ \\ = 10$

6 0

3 years ago

What are m∠1 and m∠2?

tankabanditka [31]

Answer:

Not enough information

4 0

2 years ago