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3 years ago

How can the difference in the brightness of spectral lines be explained

Chemistry

1 answer:

Nikitich [7]3 years ago

3 0

Answer:

The brightness of a line depends on the number of electrons making that transition.

Explanation:

In atomic spectra, some electronic transitions are “forbidden” by the rules of quantum mechanics. That is, some transitions are less probable than others.

The brightness of a given line depends on the number of electrons making that transition.

Allowed transitions will give the brightest lines. The brightness of the other lines will vary depending on how likely the transitions are.

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PLEASE ANSWER THIS QUESTION FAST :(

kramer

Mol sulfuric acid = 19 g * (1 mol) / (98.1 g) = 0.19367 mol
mol H2O = 0.19367 mol H2SO4 * (2 H2O) / (1 H2SO4)
= 0.387359 mol H2O
grams H2O = 0.387359 mol H2O * (18 g)/(1 mol)
= 6.97 g
The answer is 7.0 grams of water

6 0

3 years ago

Complete the following reaction. 14N+ on →?C+1H 18C 14 1 C 18C

CaHeK987 [17]

Answer: The complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

Explanation:

When nucleus of two or more atoms are bombarded together then it leads to the formation of new particles with new identity. This type of reaction are called nuclear reaction.

For example, $^{14}_{7}N + ^{1}_{0}n \rightarrow ?C + ^{1}_{1}H$

Here, nitrogen atom when bombarded with a neutron then it is forming hydrogen and a carbon atom.

As total atomic mass on reactant side is (14 + 1) = 15

So, the atomic mass of carbon formed on product side is (15 - 1) = 14.

The number of protons holded by this carbon atom is (7 - 1) = 6.

Therefore, we can conclude that the complete reaction is as follows.

$^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H$

6 0

3 years ago

How many grams of KCN are in 10.0 ml of a 0.10 M solution?

attashe74 [19]

Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{no. of moles}{Volume in liter}$

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

Molarity = $\frac{no. of moles}{Volume in liter}$

0.10 M = $\frac{no. of moles}{0.01 L}$

no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

No. of moles = $\frac{mass}{molar mass}$

0.001 mol = $\frac{mass}{65.12 g/mol}$

mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

3 0

3 years ago

Nitric monoxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO₂), a dark brown gas. If 5.895 mol of NO is mixed with 2

Schach [20]

Answer:

Limiting reactant: O2

grams NO2 produced = 230.276 g NO2

grams of NO unused = 26.67 gNO

Explanation:

2NO + O2 --> 2NO2

Step 1: Determine the molar ratio NO:O2

molar ratio NO:O2 = 5.895: 2.503 = 2.35

stoichiometric molar ratio NO:O2 = 2:1

So, O2 is the limiting reactant.

Step2: Determine the grams of NO2:

?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2

Step 3: Determine the amount of excess reagent unreacted

moles excess NO reacted = moles O2 x (2 moles NO/1 mol O2) = 2.503 x 2 = 5.006 moles NO reacted

moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted

mass NO unreacted = moles NO unreacted x MM NO = 0.889 x 30 =26.67 g NO unreacted

8 0

3 years ago

A quantity of 200 mL of 0.862 M HCl (aq) is mixed with 200 mL of 0.431

Agata [3.3K]

Answer:

The answer to this question has been described in details on the screenshots attached to this question.

Thanks. Hope it helps

7 0

3 years ago