The statement which is true about <em>Atom A</em> and <em>Atom B</em> is; Choice B: <em>Atom B will give up electrons to form bonds.</em>
According to the question;
For Atom A:
- the electron configuration is; <em>1s²2s²2p³</em>
- Therefore, it has 5 valence electrons.
For atom B:
- the electron configuration is; <em>1s²2s²2p⁶3s²3p¹</em>
- Therefore, it has 3 valence electrons.
Since, electrons need 8 electrons to assume a full octet;
Consequently, Atom B will give up electrons to become stable.
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sp3d2 hybridization has 1s, 3p and 2d orbitals, that undergo intermixing to form 6 identical sp3d2 hybrid orbitals. These 6 orbitals are directed towards the corners of an octahedron. They are inclined at an angle of 90 degrees to one another.
<h3>Which orbitals hybridize to form hybrid orbitals?</h3>
For each carbon, one 2s orbital and two 2p orbitals hybridize to form three sp2 orbitals. These hybridized orbitals align themselves in the trigonal planar structure. For each carbon, two of these sp orbitals bond with two 1s hydrogen orbitals through s-sp orbital overlap.
<h3 /><h3>What is sp3d2 hybridization?</h3>
Intermixing of one 's', three 'p' and two 'd' orbitals of almost same energy by giving six identical and degenerate hybrid orbitals is called sp3d2 hybridization. These six sp3d2 orbitals are arranged in octahedral symmetry by making 90° angles to each other.
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Sometimes true depending on your problem
