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iogann1982 [59]
3 years ago
13

How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti

on to produce a 0.5 M solution of NaCl?
Chemistry
1 answer:
kolezko [41]3 years ago
6 0

Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is 58.4\ g/mole .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g

Hence , this is the required solution.

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Step 1: Convert 156 g Cr₂S₃ to moles

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Step 2: Find conversion from Cr₂S₃ to Cr₂O₃

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Step 3: Use Dimensional Analysis

0.779182 mol Cr₂S₃ · \frac{1 \hspace{2} mol \hspace{2} Cr_2O_3}{1 \hspace{2} mol \hspace{2} Cr_2S_3} = 0.779182 mol Cr₂O₃

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Step 4: Convert moles to grams

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O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol

0.779182 mol Cr₂O₃ · 152.00 g/mol = 118.436 g Cr₂O₃

118.436 g Cr₂O₃ ≈ 118 g Cr₂O₃ (3 significant figures)

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