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Daniel [21]
4 years ago
11

Nio conducts a science experiment. He puts yeast into a bottle with water and sugar, and then caps the bottle with a balloon. He

returns two hours later and notices there are bubbles on the surface of the mixture in the bottle and that the balloon has inflated, but there are no other apparent changes.
What most likely happened?

a non-chemical change, because there are no indicators of chemical changes taking place
a chemical change, because the mixture changed color
a chemical change, because a gas was produced
a non-chemical change, because the changes that occurred are reversible
Chemistry
1 answer:
skad [1K]4 years ago
4 0

Answer:the answer is a chemical change, because a gas was produced

Explanation:  yeast is a chemical

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Which pair of atoms is held together by a covalent bond HCl LiCl NaCl KCl​
Luda [366]

Answer:

HCL

Explanation:

Covalent bond are formed between non metals so look for the pair of non metal atoms and this would be hydrogen chloride (HCL)

8 0
3 years ago
Which equation represents the combined gas law?
stealth61 [152]

Answer:

P1V1/T1= P2V2/T2

Explanation:

Combined gas law involves Boyle's law and Charles law altogether with the formula of Boyle's law as P1V1=P2V2

formula for charles law as V1/T1=V2/T2

so when combined form P1V1/T1=P2V2/T2

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3 years ago
A solid-solid solution is called a(n)
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Hydrogen gas reacts with chlorine gas to form hydrogen chloride as shown in the following reaction: H2 (9) + Cl2 (g) + 2HCl (9)
vivado [14]

Answer:

467

Explanation:

ncl2 = 454.4x1/(71.0 g/mol) = 6.40 mols cl2

6.40 mols cl2 x 2molsHCL/1moleCL2 x 36.5g/1moleHCL = <u>467 g HCL</u>

8 0
3 years ago
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A mixture of 117.9 g of P and 121.8 g of O, reacts completely to form P4O6 and P4O10. Find the masses of P4O6 and P4O10
Alex17521 [72]

Answer:

Mass of P4O6=103.4

            P4O10=133.48

Explanation:

Balanced reaction is:

8P +8O_{2}  ⇒P_{4} O_{6} +P_{4} O_{10}

Both reactant completely vanishes as equivalent of bot are equal.

Moles of P=\frac{117.9}{31} =3.80

Moles of O_{2} =\frac{117.9}{31} =3.80

No. of moles of formed product are equal and is \frac{1}{8}th of mole of any of reactant.

Thus weight of  P_{4} O_{6} =\frac{3.80}{8}×220 ≈103.41

        weight of  P_{4} O_{10} =\frac{3.80}{8}×284 ≈133.48

4 0
3 years ago
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