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Sholpan [36]
3 years ago
15

Cl2(aq) + H2O H+(aq) + Cl–(aq) + HOCl(aq)

Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0
44. (a) N2O3 (b) SF4 (c) AlCl3 (d) Li2CO3 46. H Br δ+ δ− 48. The metallic potassium atoms lose one electron and form +1 cations, and the nonmetallic fluorine atoms gain one electron and form –1 anions. K → K+ + e– 19p/19e– 19p/18e– F + e– → F– 9p/9e– 9p/10e– The ionic bonds are the attractions between K+ cations and F– anions. 50. See Figure 3.6. 52. (a) covalent…nonmetal-nonmetal (b) ionic…metal-nonmetal 54. (a) all nonmetallic atoms - molecular (b) metal-nonmetal - ionic 56. (a) 7 (b) 4 58. Each of the following answers is based on the assumption that nonmetallic atoms tend to form covalent bonds in order to get an octet (8) of electrons around each atom, like the very stable noble gases (other than helium). Covalent bonds (represented by lines in Lewis structures) and lone pairs each contribute two electrons to the octet. (a) oxygen, O If oxygen atoms form two covalent bonds, they will have an octet of electrons around them. Water is an example: H O H (b) fluorine, F If fluorine atoms form one covalent bond, they will have an octet of electrons around them. Hydrogen fluoride, HF, is an example: H F (c) carbon, C If carbon atoms form four covalent bonds, they will have an octet of electrons around them. Methane, CH4, is an example: H H H H C (d) phosphorus, P If phosphorus atoms form three covalent bonds, they will have an octet 
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At 35°C and 2 atm of pressure, the volume of gas is 200 ml. If the temperature changes to
lys-0071 [83]

Answer:

V₂ = 106.5 mL

Explanation:

Given data:

Initial volume =200 mL

Initial pressure = 2 atm

Initial temperature = 35 °C (35 +273 = 308 K)

Final temperature = 55°C (55+273 = 328 K)

Final volume = ?

Final pressure = 4 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2 atm ×200 mL × 328 K / 308 K ×4 atm

V₂ = 131200 atm .mL. K / 1232 K.atm

V₂ = 106.5 mL

6 0
2 years ago
Which statment correctly decribes a law?
xeze [42]
B) is a factual statement
Laws are based on observations and experiments and have been tested many, many times to show no error
4 0
3 years ago
1. A gas has a volume of 140L at 37 ºC and 620 kpa pressure. Calculate its volume at STP.
solniwko [45]

Answer:

1. Volume as STP = 755 L

2. Outside temperature = 255 K

3. Percentage yield = 70.5%

Explanation:

1. At STP, pressure  = 101.3 kpa, temperature  = 0°C or 273.15 K

Using the general gas equation :

P1V1/T1 = P2V2/T2

P1 = 620 kpa

V1 = 140 L

T1 = 37°C or (273.15 + 37) K = 310.15 K

P2 = 101.3 kpa

V2 = ?

T2 = 273.15 K

V2 = P1V1T2/P2T1

V2 = 620 × 140 × 273.15 / 101.3 × 310.15

V2 = 755 L

2. Using Charles' gas law:

V1/T1 = V2/T2

V1 = 2.5 L

T1 = 290 K

V2 = 2.2 L

T2 = ?

T2 = V2T1/VI

T2 = 2.2 × 290 / 2.5

T2 = 255 K

3. Equation of reaction : 2 Al + 3 CuSO4 ---> Al2 (SO4)3 + 3 Cu

From equation of the reaction,  2 moles of Al produces 3 moles of Cu

Molar mass of Al = 27 g; Molar mass of Cu = 63.5 g

2 moles of Al = 2 × 27 g = 54 g; 3 moles of Cu = 3× 63.5 = 190.5 g

54 g of Al produces 190.5 g of Cu

1.87 g of Al will produce 190.5/54 × 1.87 g of Cu = 6.60 g of Cu

Percentage yield = actual yield /theoretical yield × 100%

Percentage yield = 4.65/6.60 × 100%

Percentage yield = 70.5%

5 0
3 years ago
Fission and Fusion of Atomic Nuclei:
bogdanovich [222]

Answer:

C B A D

Explanation:

6 0
3 years ago
Calculate the molar mass of Al(CH3O2)3
lina2011 [118]

Answer:

The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.

Explanation:

6 0
3 years ago
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