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stich3 [128]
2 years ago
11

Find gas pressure of 2.5 moles H2 and 4.6 moles Ne at 1400mmHg.

Chemistry
1 answer:
Monica [59]2 years ago
5 0

Answer:

Pressure of neon = 1.17 atm

Pressure of hydrogen = 0.63 atm

Explanation:

Given data:

Number of moles of H₂ = 2.5 mol

Number of moles of Ne = 4.6 mol

Total pressure = 1400 mmHg (1400/760 = 1.8 atm)

Solution:

We will solve this problem through mole fraction method.

Total number of moles = 2.5 + 4.6 = 7.1

Mole fraction of H₂                                         Mole fraction of Ne

2.5 mol/7.1 mol= 0.35                                     4.6mol/7.1mol = 0.65

Pressure of hydrogen = 0.35 × 1.8 atm

Pressure of hydrogen = 0.63 atm

Pressure of neon = 0.65 × 1.8 atm

Pressure of neon = 1.17 atm

Total pressure which is already given is sum of partial pressure of hydrogen and neon gas.

0.63 atm + 1.17 atm = 1.8 atm

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dybincka [34]

Your Welcome.

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4 0
2 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

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3 years ago
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nexus9112 [7]
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Ainat [17]

Answer:

Explanation:

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finlep [7]

Answer:

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Explanation:

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