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stich3 [128]
3 years ago
11

Find gas pressure of 2.5 moles H2 and 4.6 moles Ne at 1400mmHg.

Chemistry
1 answer:
Monica [59]3 years ago
5 0

Answer:

Pressure of neon = 1.17 atm

Pressure of hydrogen = 0.63 atm

Explanation:

Given data:

Number of moles of H₂ = 2.5 mol

Number of moles of Ne = 4.6 mol

Total pressure = 1400 mmHg (1400/760 = 1.8 atm)

Solution:

We will solve this problem through mole fraction method.

Total number of moles = 2.5 + 4.6 = 7.1

Mole fraction of H₂                                         Mole fraction of Ne

2.5 mol/7.1 mol= 0.35                                     4.6mol/7.1mol = 0.65

Pressure of hydrogen = 0.35 × 1.8 atm

Pressure of hydrogen = 0.63 atm

Pressure of neon = 0.65 × 1.8 atm

Pressure of neon = 1.17 atm

Total pressure which is already given is sum of partial pressure of hydrogen and neon gas.

0.63 atm + 1.17 atm = 1.8 atm

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Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

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<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

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Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

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The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

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