Answer:
94.2 g/mol
Explanation:
Ideal Gases Law can useful to solve this
P . V = n . R . T
We need to make some conversions
740 Torr . 1 atm/ 760 Torr = 0.974 atm
100°C + 273 = 373K
Let's replace the values
0.974 atm . 1 L = n . 0.082 L.atm/ mol.K . 373K
n will determine the number of moles
(0.974 atm . 1 L) / (0.082 L.atm/ mol.K . 373K)
n = 0.032 moles
This amount is the weigh for 3 g of gas. How many grams does 1 mol weighs?
Molecular weight → g/mol → 3 g/0.032 moles = 94.2 g/mol
Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,
Where, m is mass of iron
s is specific heat of iron
d T is change in temperature in celcius
If
1 cal = 4.2 J
Then,
Thus 0.389 k cal of enrgy is required by a 15.6 g Fe to reach to 355 C^0
Answer:
a measure of the suitability of water for a particular use based on selected physical, chemical, and biological characteristics.
Answer:
Explanation:
<u>1) Determine the molar mass of the heptane</u>
element # of atoms atomic mass total mass
C 7 12.011 g/mol 7×12.011 g/mol = 84.077 g/mol
H 16 1.008 g/mol 16×1.008 g/mol = 16.128 g/mol
-------------------
Molar mass = 100.205 g/mol
<u>2) Percent of carbon, %</u>
- % = (mass of element / molar mass )×100
= (84.077 g/mol / 100.205 g/mol )×100 = 83.83 %
- Round to two significant figures: 84% ← answer
Answer:
Partial pressure O₂ = 1.78 atm
Explanation:
We can apply the mole fraction to solve the question:
Moles of gas / Total moles = Partial pressure of gas / Total pressure
Total moles = 1 H₂ + 2.5 He + 2O₂ = 4.5 moles
2 mol O₂ / 4.5 mol = Partial pressure O₂ / 4 atm
(2 mol O₂ / 4.5 mol ) . 4 atm = Partial pressure O₂ → 1.78 atm
