En un viaje ida y vuelta de 10 kilómetros, el desplazamiento y la distancia recorrida son respectivamente.

What is the differential equation governing the growth of current in the circuit as a function of time after t=0? express the ri

Reika [66]

Answer:

$v_{b}=ir+L\frac{di}{dt}$

Explanation:

A differential equation that contain a term with di(t)/dt is in a RL circuit. Here we have

$v_{b}=v_{r}+v_{i}$

where vr is the voltage in the resistance, vi is the voltage in the inductance and vb is the source voltage. But also we have that

$v_{r}=ir\\v_{i}=L\frac{di}{dt}$

where L is the inductance of the circuit, r is the resistance an i is the current. By replacing we have the differential equation

$v_{b}=ir+L\frac{di}{dt}$

I hope this is useful for you

regards

3 0

3 years ago

Suppose that the inverse market demand for silicone replacement tips for Sony earbud headphones is p = pN - 0.1Q, where p is t

lbvjy [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The effect of a change in the price of a new pair of headphones on the equilibrium price of replacement tips ( dp/dpN) is

$\frac{\delta p}{\delta p_N} =1$

b

The value of Q and p at equilibruim is

$Q_e = 250$ and $p_d =$ 5

The consumer surplus is $C= 3125$

The producer surplus is $P = 375$

Explanation:

From the question we are told that

The inverse market demand is $p_d = p_N -0.1Q$

The inverse supply function is $p_s = 2+ 0.012Q$

a

The effect of change in the price is mathematically given as

$\frac{\delta p}{\delta p_N}$

Now differntiating the inverse market demand function with respect to $p_N$

We get that

$\frac{\delta p}{\delta p_N} =1$

b

We are told that $p_N =$ $30

Therefore the inverse market demand becomes

$p_d = 30 -0.1Q$

At equilibrium

$p_d = p_s$

So we have

$30 -0.1Q_e = 2+ 0.012Q_e$

Where $Q_e$ is the quantity at equilibrium

$28 = 0.112Q_e$

$Q_e = \frac{28}{0.112}$

$Q_e = 250$

Substituting the value of Q into the equation for the inverse market demand function

$p_d = 30 - 0.1 (250 )$

$p_d =$ 5

Looking at the equation for $p_d \ and \ p_s$ we see that

For Q = 0

$p_d = 30$

$p_s =2$

And for Q = 250

$p_d = 5$

$p_s = 5$

Hence the consumer surplus is mathematically evaluated as

$C = \frac{1}{2} * Q_e * (30 -5)$

Substituting value

$C = \frac{1}{2} * 250 (30-5)$

$C= 3125$

And

The producer surplus is mathematically evaluated as

$P = \frac{1}{2} *250 * (5-2)$

$P = 375$

4 0

3 years ago

One would use deductive reasoning to

Ivan

The answer is Prove a hypothesis

5 0

3 years ago

Kelly pushes a shopping cart with a force of 42 N. The mass of the shopping cart is 24 kg. Calculate the acceleration of the sho

damaskus [11]

Answer:just use a calculator

Explanation:

3 0

3 years ago

A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of

pishuonlain [190]

Answer:

Explanation:

a ) gauge pressure will be due to water column of length 15 cm .

pressure = h d g , h is height of column , d is density of column and g is gravitational acceleration .

= .15 x 10³ x 9.8

= 1470 Pa .

b )

Let due of weight of water column , mercury level in left column goes down by distance h . The level of mercury in right column will rise by the same distance ie by distance h .

So mercury column of 2h height is balancing the water column of height 15 cm

2h x 13.6 x 10³ x g = .15 x 10³ x g

h = .15 / (2 x 13.6)

= .55 x 10⁻² m

= . 55 cm

Difference of height of water column and mercury column

= 15 - 2 x .55 cm

= 13.9 cm .

3 0

3 years ago