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The force of friction is equal to the product of the vertical force applied by the surface to the object in the coefficient of friction.
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In this question ,
surface vertical force = Weight of the object
Thus ;
svf = ( mass ) × ( gravity acceleration )
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If gravity acceleration is 10 :
svf = 10 × 10 = 100 N
So ;
frictional force = 100 × 0.20
frictional force = 20 N
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If gravity acceleration is 9.8 :
svf = 10 × 9.8 = 98 N
So ;
frictional force = 98 × 0.20
frictional force = 19.6 N
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Answer:
Friction force always acts tangent to the surface at points of contact. Friction force acts opposite to the direction of motion. There are 2 types of friction: Static friction: If the two surfaces in contact do not move relative to each other, one has static friction.
1. Amperes, is the SI unit (also a fundamental unit) responsible for current.
2. 
Δq over Δt technically
Rearrange for Δq
I x Δt = Δq
1.5mA x 5 = Δq
Δq = 0.0075
Divide this by the fundamental charge "e"
Electrons: 0.0075 / 1.60 x 10^-19
Electrons: 4.6875 x 10^16 or 4.7 x 10^16
3. So we know that the end resistances will be equal so:
ρ = RA/L
ρL = RA
ρL/A = R
Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper
We are looking for L2 so we can isolate using algebra to get:
If you fill in those values you get 0.0205
or 2.05 cm
<h3>
Answer:</h3>
1.3 Amps
<h3>
Explanation:</h3>
<u>We are given;</u>
A circuit with resistors, R1 and R2
R1 = 7 Ω
R2 = 11 Ω
Voltage = 24 V
We are required to calculate the current in the circuit.
<h3>Step 1: We need to find the effective resistance.</h3>
When resistors are arranged in series, the effective resistance is calculated by;
Rt = R₁ + R₂ + R₃ + ..........Rₙ
Therefore;
Total resistance = 7 + 11
= 18 Ω
<h3>Step 2: Calculate the current in the circuit</h3>
From the ohm's law;
V = IR
Rearranging the formula;
I = V/R
Thus;
I = 24 V ÷ 18 Ω
= 1.333 Amps
= 1.3 Amps
Thus, the current in the circuit is 1.3 Amps
