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Lyrx [107]
3 years ago
13

What two factors affect projectile motion? A) distance and angle B) distance and amplitude C) initial velocity and angle D) init

ial velocity and amplitude
Physics
1 answer:
maksim [4K]3 years ago
4 0

Answer:

C) Initial velocity and angle

Explanation:

The path of the projectile motion is a parabolic path. The motion of a projectile motion is studied by splitting the motion into 2 mutually perpendicular components; one along the horizontal x axis and other vertical y axis.

The position of the projectile at any time t is given as:

x=ut\cos \theta\\y=ut\sin \theta - \frac{1}{2}gt^2

Where,

u\rightarrow \textrm{Initial velocity}\\v\rightarrow \textrm{Final velocity}\\\theta\rightarrow \textrm{Angle of projection}\\g\rightarrow \textrm{Acceleration due to gravity}

From the above equations, we conclude that,

The projectile motion depends on two factors:

i. Initial velocity (u)

ii. Angle of projection (\theta)

Option C is correct.

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3. Ecology
Korvikt [17]

Answer:

The family would not have hot water unless they were to heat the the water. They would have to depend on the stove in order to survive by heating the house to say alive and not freeze. They would also have to depend on the stove to get hot water to do any, but if the sun goes away for too long and everything starts to die then they will have to use what food and wood that they have in order to survive.

Explanation:

6 0
3 years ago
A car is traveling at 100 km/h when the driver sees an accident 80 m ahead and slams on the brakes. what minimum constant decele
Effectus [21]
Assuming the driver starts slamming the brakes immediately, the car moves by uniformly decelerated motion, so we can use the following relationship
2aS = v_f^2 - v_i^2 (1)
where 
a is the deleceration
S is the distance covered after a time t
v_f is the velocity at time t
v_i=100 km/h = 27.8 m/s is the initial speed of the car

The accident is 80 m ahead of the car, so the minimum deceleration required to avoid the accident is the value of a such that S=80 m and v_f=0 (the car should stop exactly at S=80 m to avoid the accident). Using these data, we can solve  the equation (1) to find a:
a=- \frac{v_i^2}{2 S}= -\frac{(27.8 m/s)^2}{2 \cdot 80 m} =-4.83 m/s^2
And the negative sign means it is a deceleration.

4 0
3 years ago
A prism of angle 60° is of a material of refractive index √√2. Calculate angles of minimum deviation and maximum deviation.​
Tom [10]

Answer:

i don't know if this helps but The refractive index of the material of the prism of an angle 60 degree is 1.62 for sodium light. there you go hope it helps

Explanation:

5 0
2 years ago
A 0.150-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wa
Hitman42 [59]

Answer:

The magnitude of the change in momentum of the stone is 5.51kg*m/s.

Explanation:

the final kinetic energy = 1/2(0.15)v^2

                1/2(0.15)v^2  = 70%*1/2(0.15)(20)^2

                              v^2 = 21/0.075

                              v^2 = 280

                                 v = 16.73 m.s

if u is the initial speed and v is the final speed, then:

u = 20 m/s and v = - 16.73m/s

change in momentum = m(v-u)

                                     = 0.15(- 16.73-20)

                                    = -5.51 kg*m.s

Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.

3 0
3 years ago
When using a different calorimeter, and mixing 50 ml of hot water at 65 degrees c with 60 ml of water in the calorimete
Paha777 [63]

The specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.

<h3>Conseervation of energy</h3>

The heat capacity of the calirometer is determined by applying the principle of conservation of energy.

Heat lost by the hot water = Heat gained by the calirometer

Q _w = Q_c\\\\M_w C_w\Delta \theta _w = M_c C_c\Delta \theta _c

where;

  • M is mass

mass = density x volume = ρV

Density of water = 1 g/ml

Mass of hot water = 1 x (50) = 50 g

Mass of water in calorimeter = 1 x (60) = 60 g

<h3>Equilibrium temperature</h3>

\Delta T_c = 5.5\\\\T - 25 = 5.5\\\\T = 30.5 \ ^0C

<h3>Specific heat capacity of the calirometer</h3>

50 \times 4.184 \times (65 - 30.5) = 60 \times C_c \times (30.5 - 25)\\\\7217.4 = 330C_c\\\\C_c = \frac{7217.4}{330} \\\\C_c = 21.87 \ J/g^0C

Thus, the specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.

The complete question is below

When using a different calorimeter, and mixing 50 ml of hot water at

65 degrees C with 60 ml of water in the calorimeter at 25 degrees C, the temperature of the calorimeter increased by 5.5 degrees C.

a. Calculate the heat capacity of this calorimeter?

Learn more about heat capacity here: brainly.com/question/16559442

5 0
2 years ago
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