Answer:
i speak english not spanigh sorry :(
Explanation:
Explanation:
Given Data
Total mass=93.5 kg
Rock mass=0.310 kg
Initially wagon speed=0.540 m/s
rock speed=16.5 m/s
To Find
The speed of the wagon
Solution
As the wagon rolls, momentum is given as
P=mv
where
m is mass
v is speed
put the values
P=93.5kg × 0.540 m/s
P =50.49 kg×m/s
Now we have to find the momentum of rock
momentum of rock = mv
momentum of rock = (0.310kg)×(16.5 m/s)
momentum of rock =5.115 kg×m/s
From the conservation of momentum we can find the wagons momentum So
wagon momentum=50.49 -5.115 = 45.375 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
Speed of wagon=45.375/(93.5-0.310)
Speed of wagon= 0.487 m/s
Throwing rock backward,
momentum of wagon = 50.49+5.115 = 55.605 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)
speed of wagon= 0.5967 m/s
a. 27
after that all you need to do is use the work formula as you will be able to acheive results
Answer:
they cant travel through a vacuum
Answer:
c. P₁/T₁=P₂/T₂
Explanation:
neither Avogadro’s, Charles’, or Boyle’s law formula can be used, since some parameters like volume is not given,
to find P₂, given P₁, T₁, and T₂ we will therefore use Gay-lussac's law.
gay lussacs law state that, provided volume is kept constant, pressure is directly proportional to temperature.
the volume volume is said to be filled, i.e its is kept constants when temperature is change
