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Naily [24]
3 years ago
6

B) into the same funnel is poured carefully 50 ml of hexane (density = 0.660 g/ml) so that the other two layers are not disturbe

d. the hexane forms a third layer. the funnel is stoppered and the mixture is shaken vigorously. after standing, two layers separate. which compound(s) are in which layer?
Chemistry
1 answer:
Annette [7]3 years ago
4 0
The substances that are added in the funnel are bromoethane or CH3CH2Br, water and hexane. The density of the bromoethane is given as 1.460 g/mL, density of water would 1 g/mL and hexane would have a density of 0.660 g/mL. Assuming that these substances are immiscible in each other, adding them in a funnel would form three layers. The substance with the highest density would be in the lowest layer which is bromoethane. In the middle layer, water could be found. Lastly, hexane would be found on the uppermost layer since it is the substance that has the lowest density of the three.
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The answer is C. Since aluminum reacts with chloride displacing only Copper.
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A solution's ph is a measure of what? strength or weakness acid dissociation constant hydronium ion concentration molarity perce
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Use the following equation to answer the questions below.
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Answer:

1-Double replacement

Explanation:

3 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
4 years ago
What is the reaction quotient?
ikadub [295]

Answer:

A. It measures the [products] / [reactants].

Explanation:

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  • Reaction quotient (Q) =  [products] / [reactants]

So, the right choice answer:

A. It measures the [products] / [reactants].

5 0
3 years ago
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