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Naily [24]
3 years ago
6

B) into the same funnel is poured carefully 50 ml of hexane (density = 0.660 g/ml) so that the other two layers are not disturbe

d. the hexane forms a third layer. the funnel is stoppered and the mixture is shaken vigorously. after standing, two layers separate. which compound(s) are in which layer?
Chemistry
1 answer:
Annette [7]3 years ago
4 0
The substances that are added in the funnel are bromoethane or CH3CH2Br, water and hexane. The density of the bromoethane is given as 1.460 g/mL, density of water would 1 g/mL and hexane would have a density of 0.660 g/mL. Assuming that these substances are immiscible in each other, adding them in a funnel would form three layers. The substance with the highest density would be in the lowest layer which is bromoethane. In the middle layer, water could be found. Lastly, hexane would be found on the uppermost layer since it is the substance that has the lowest density of the three.
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This looks like a question in which we can use the Combined Gas Law to calculate the volume.

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Data:

\begin{array}{rclrclrcl}p_{1}& =& \text{2 atm}\qquad & V_{1} &= & \text{10 L}\qquad & T_{2}& =& \text{400 K}\\p_{2}& =& \text{4 atm}\qquad & V_{2} &= & \text{?}\qquad & T_{2}& =& \text{800 K}\\\end{array}

Calculation:

\begin{array}{rcl}\dfrac{2 \times 10}{400}& =& \dfrac{4V_{2} }{800}\\\\0.050& = &0.0050V_{2}\\V_{2}& = &\mathbf{10 L}\end{array}\\\text{The final volume is }\boxed{\textbf{10 L}}

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