Question

The nardo ring is a circular test track for cars. it has a circumference of 12.5 km. cars travel around the track at a constant speed of 100 km/h. a car starts at the easternmost point of the ring and drives for 7.5 minutes at this speed. what is the magnitude of the car's displacement, in km, from its initial position?

Answer 1

The magnitude of the car's displacement is 0 m

Further explanation

Acceleration is rate of change of velocity.

$\large {\boxed {a = \frac{v - u}{t} } }$

$\large {\boxed {d = \frac{v + u}{2}~t } }$

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let us now tackle the problem!

Given:

Circumference = C = 12.5 km

Speed = v = 100 km/h

Time = t = 7.5 minutes = 0.125 h

Unknown:

Displacement = d = ?

Solution:

Firstly, we will calculate the distance traveled by the car.

$Distance = Speed \times Time$

$Distance = 100 ~ km/h \times 0.125 ~ h$

$\large {\boxed {Distance = 12,5 ~ km} }$

Since the circumference of the track is equal to the distance traveled by the car, the car returns to its starting point.

This means that the displacement made by the car is 0 m.

Learn more

• Velocity of Runner : brainly.com/question/3813437

• Kinetic Energy : brainly.com/question/692781

• Acceleration : brainly.com/question/2283922

• The Speed of Car : brainly.com/question/568302

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Answer 2

In physical science, there are two types of quantities. The scalar quantity and the vector quantity. The scalar quantity has only the magnitude while the vector quantity has both the magnitude and direction. Displacement is the distance from the starting point to the end point of an object.

The distance traveled by an object can be calculated by the equation,
               D = s x t
where D is the distance, s is the speed, and t is time. 
Note to convert the given dimensions properly to be able to cancel units from numerator and denominator of the fraction.
             D = (100 km/h)(7.5 min)(1 h/60 min) = 12.5 km

This means that the object was just back to the original point. Hence, the displacement is equal to ZERO.