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UNO [17]
3 years ago
12

Solutions with a higher concentration of solutes than the concentration inside the cell are: Solutions with a higher concentrati

on of solutes than the concentration inside the cell are:
a. hypertonic.
b. isotonic.
c. hyperosmotic.
d. hypotonic.
Chemistry
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

A

Explanation:

A hypertonic solution is one in which the concentration of the solute is greater than that of those inside the cell. This means that there is a solution with a higher concentration of solute compared to what is obtainable inside the cell environment.

Hence, we say that the solutions are hypertonic since they contain essentially solutes that are more concentrated than those inside the cell

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Answer:

3 atoms of carbon

Explanation:

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2 years ago
Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride. Wright the formula equation f
NeX [460]

Answer:

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Explanation:

From the question, we were told that:

Iron(III) sulfide reacts with hydrochloric acid to produce hydrogen sulfide and iron(II) chloride.

Please note that elemental sulphur is produced along with this reaction. The equation for the reaction is given below:

Fe2S3 + HCl —> H2S + FeCl2 + S

Now, we can balance the equation as shown below:

There are 3 atoms of S on the left side of the equation and 2 atoms on the right. It can be balance by putting 2 in front of H2S as shown below:

Fe2S3 + HCl —> 2H2S + FeCl2 + S

Now, we have 4 atoms of H on the right side and 1atom on the left side. It can be balance by putting 4 in front of HCl as shown below:

Fe2S3 + 4HCl —> 2H2S + FeCl2 + S

Also, there are 4 atoms of Cl on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of FeCl2 as shown below:

Fe2S3 + 4HCl —> 2H2S + 2FeCl2 + S

Now, we can see that the equation is balanced

5 0
3 years ago
Bubbling and fizzing are the products of a chemical reaction. Which substances are the reactants?
7nadin3 [17]
B. Vinegar and Baking soda :)
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3 years ago
A. The ivy had more genes than the cactus
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The answer is c ..............::
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3 years ago
). In a titration, a student obtained an average titre value of 3.9 cm3 of 0.3 M HCl. If the volume of Na2CO3 solution used is 1
Oliga [24]

Answer:

I) 0.0585 M

ii)6.2 g dm-3

Explanation:

The reaction equation is given as;

Na2CO3(aq) +2HCl(aq)------> 2NaCl(aq) + CO2(g) +H2O(l)

Concentration of acid CA= 0.3 M

Volume of acid VA= 3.9 cm^3

Concentration of base CB= the unknown

Volume of base VB= 10 cm^3

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB=CBVBNA

CB= CAVANB/VBNA

substituting values;

CB= 0.3 × 3.9 × 1/ 10.0 × 2

CB= 0.0585 M

ii) mass concentration= molar concentration × molar mass

Molar mass of Na2CO3= 106 gmol-1

Mass concentration= 0.0585 × 106 = 6.2 g dm-3

5 0
3 years ago
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