<span>The law of conservation of energy applies to a light bulb because the energy is being transformed into light and the light bulb is acting as a catalyst. The light bulb itself is not a form of energy, however when in combination with the electrical outlet to the bulb the electricity heats up the metal interior forming it into light. according to the law of conservation energy cannot be created or destroyed, but instead is formed into different kinds of energy. In relation to a light bulb electrical currents are forming heat energy by heating up the metal interior, then the bulb or glass around it allows to radiate light.</span>
Magnitude of the force of tension: 139 N
Explanation:
The surface of the ramp here is assumed to be the positive x-direction.
To solve this problem and find the magnitude of the force of tension, we have to analyze only the situation along the x-direction, since the force of tension lie in this direction.
There are three forces acting along the x-direction:
- The force of tension,
, acting up along the plane - The force of friction,
, acting down along the plane - The component of the weight in the x-direction,
, acting down along the plane
We know that the magnitude of the weight is
![F_g=70.0 N](https://tex.z-dn.net/?f=F_g%3D70.0%20N)
So its x-component is
![F_{gx}=F_g sin \theta =(70.0)(sin 22^{\circ})=26.2 N](https://tex.z-dn.net/?f=F_%7Bgx%7D%3DF_g%20sin%20%5Ctheta%20%3D%2870.0%29%28sin%2022%5E%7B%5Ccirc%7D%29%3D26.2%20N)
The net force along the x-direction can be written as
![F_x = F_T-F_f-F_{gx}](https://tex.z-dn.net/?f=F_x%20%3D%20F_T-F_f-F_%7Bgx%7D)
And therefore, since the net force is 98 N, we can find the magnitude of the force of tension:
![F_T=F_x+F_f+F_{gx}=98+14.8+26.2=139 N](https://tex.z-dn.net/?f=F_T%3DF_x%2BF_f%2BF_%7Bgx%7D%3D98%2B14.8%2B26.2%3D139%20N)
Learn more about inclined planes:
brainly.com/question/5884009
#LearnwithBrainly
Answer:
![v=12.65\ m.s^{-1}](https://tex.z-dn.net/?f=v%3D12.65%5C%20m.s%5E%7B-1%7D)
Explanation:
Given:
- mass of vehicle,
![m=1350\ kg](https://tex.z-dn.net/?f=m%3D1350%5C%20kg)
- radius of curvature,
![r=71\ m](https://tex.z-dn.net/?f=r%3D71%5C%20m)
- coefficient of friction,
![\mu=0.23](https://tex.z-dn.net/?f=%5Cmu%3D0.23)
<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>
![m.\frac{v^2}{r} =\mu.N](https://tex.z-dn.net/?f=m.%5Cfrac%7Bv%5E2%7D%7Br%7D%20%3D%5Cmu.N)
where:
coefficient of friction
normal reaction force due to weight of the car
velocity of the car
![1350\times \frac{v^2}{71} =0.23\times (1350\times 9.8)](https://tex.z-dn.net/?f=1350%5Ctimes%20%5Cfrac%7Bv%5E2%7D%7B71%7D%20%3D0.23%5Ctimes%20%281350%5Ctimes%209.8%29)
is the maximum velocity at which the vehicle can turn without skidding.
The light will bend when in