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Roman55 [17]
3 years ago
6

A child sits on a fiberglass muskrat fastened 7.2 meters from the center of a merry-go-round platform that is rotating once ever

y 15 seconds. What is the child's speed while sitting on the muskrat?
Physics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

Child's speed, v = 3.01 m/s

Explanation:

It is given that,

Radius of the merry- go- round, r = 7.2 m

Time of rotation, t = 15 seconds

Let v is the child's speed while sitting on the muskrat. The displacement of the child is,

d=2\pi r=2\pi \times 7.2=45.23\ m

The speed of the child is given by :

v=\dfrac{d}{t}

v=\dfrac{45.23\ m}{15\ s}

v = 3.01 m/s

So, the speed of child while sitting on the muskrat is 3.01 m/s. Hence, this is the required solution.

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What is one watt ? Write the relation of watt with kilowatt , megawatt , and horsepower .​
alina1380 [7]

Answer:

See the explanation below

Explanation:

The watt (the power) is equal to the relationship between the work and the time in which that work is performed.

P = W/t

where:

W = work [J] (units of Joules)

t = time [s].

Now 1000 [W] are equal to 1 [kW]

And 1000000 [W] are equal to 1 [MW]

The horsepower is the unit of power in the imperial system of units.

And 745.7 [W] are equal to 1 [Hp]

3 0
3 years ago
The noise level coming from a pig pen with
sweet [91]

Answer:

The decibel of the remaining pigs is 51.5 dB.

Explanation:

Decibel (dB) is a unit of measure of the intensity of a given sound.

Number of pigs = 199, noise level = 74.3 dB.

Given that the intensity (I) of the sound from the pen is proportional to the number of pigs (N), thus:

                       I    \alpha  N

                       I = kN

where k is the constant of proportionality.

⇒                    k = \frac{I}{N}

                         = \frac{74.3}{199}

                      k = 0.3734

When 61 numbers of pigs were removed, the number of remaining pigs (N) squealing at their original level is 138.

Thus, the becibel level (I) of the remaining pigs can be determined by:

                  I = kN

                    = 0.3734 × 138

                   = 51.53 dB

The becibel level (I) of the remaining pigs is 51.53 dB.

6 0
3 years ago
What is the direction of a vector with an x component of -12 m and a y component of -15 m?
dusya [7]

Answer:

51.34^{\circ}

Explanation:

Given that,

x component of a vector = -12 m

The y component of a vector = -15 m

We need to find the direction of a vector. The direction of a vector is given by :

\tan\theta=\dfrac{y}{x}

Put all the values,

\tan\theta=\dfrac{-15}{-12}\\\\\theta=\tan^{-1}(\dfrac{-15}{-12})\\\\\theta=51.34^{\circ}

So, the direction of vector is 51.34^{\circ} to x component.

3 0
3 years ago
In a few sentences, describe how the thermostat utilizes a bimetallic strip in order to turn a furnace on and off in one or two
Vilka [71]

Answer:

Explanation:

Bimetallic strips are used in thermostats for measuring and controlling temperature. The strip is connected to a switch and as the temperature changes, the strip flexes and opens or closes a contact. They are also used in ovens for measuring temperature. An electromechanical thermostat typically contains either a bi-metal coil or a metal strip. When the temperature changes, this coil or strip will move, causing a vial containing mercury to tip to one side. The mercury flows to one end of the vial, signaling that the heating or cooling needs to be turned on.

4 0
3 years ago
A 51-kg woman runs up a vertical flight of stairs in 5.0 s. Her net upward displacement is 5.0 m. Approximately, what average po
Vika [28.1K]

Answer:

The average power the woman exerts is 0.5 kW

Explanation:

We note that power, P = The rate at which work is done = Work/Time

Work = Energy

The total work done is the potential energy gained which is the energy due to vertical displacement

Given that the vertical displacement = 5.0 m, we have

Total work done = Potential energy gained = Mass, m × Acceleration due to gravity, g × Vertical height, h

m = 51 kg

g = Constant = 9.81 m/s²

h = 5.0 m

Also, time, t = 5.0 s

Total work done = 51 kg × 9.81 m/s²× 5 m = 2501.55 kg·m²/s² = 2501.55 J

P = 2501.55 J/(5 s) = 500.31 J/s = 500.31 W ≈ 500 W = 0.5 kW.

6 0
3 years ago
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