Question

A child sits on a fiberglass muskrat fastened 7.2 meters from the center of a merry-go-round platform that is rotating once every 15 seconds. What is the child's speed while sitting on the muskrat?

Answer 1

Answer:

Child's speed, v = 3.01 m/s

Explanation:

It is given that,

Radius of the merry- go- round, r = 7.2 m

Time of rotation, t = 15 seconds

Let v is the child's speed while sitting on the muskrat. The displacement of the child is,

$d=2\pi r=2\pi \times 7.2=45.23\ m$

The speed of the child is given by :

$v=\dfrac{d}{t}$

$v=\dfrac{45.23\ m}{15\ s}$

v = 3.01 m/s

So, the speed of child while sitting on the muskrat is 3.01 m/s. Hence, this is the required solution.