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Roman55 [17]
3 years ago
6

A child sits on a fiberglass muskrat fastened 7.2 meters from the center of a merry-go-round platform that is rotating once ever

y 15 seconds. What is the child's speed while sitting on the muskrat?
Physics
1 answer:
kodGreya [7K]3 years ago
7 0

Answer:

Child's speed, v = 3.01 m/s

Explanation:

It is given that,

Radius of the merry- go- round, r = 7.2 m

Time of rotation, t = 15 seconds

Let v is the child's speed while sitting on the muskrat. The displacement of the child is,

d=2\pi r=2\pi \times 7.2=45.23\ m

The speed of the child is given by :

v=\dfrac{d}{t}

v=\dfrac{45.23\ m}{15\ s}

v = 3.01 m/s

So, the speed of child while sitting on the muskrat is 3.01 m/s. Hence, this is the required solution.

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If an automobile had a 100%-efficient engine, transferring all of the fuel's energy to work, would the engine be warm to your to
svetlana [45]

Answer:

The engine would be warm to touch, and the exhaust gases would be at ambient temperature. The engine would not vibrate nor make any noise. None of the fuel entering the engine would go unused.

Explanation:

In this ideal engine, none of these events would happen due to the nature of the efficiency.

We can define efficiency as the ratio between the used energy and the potential generable energy in the fuel.

n=W, total/(E, available).

However, in real engines the energy generated in the combustion of the fuel transforms into heat (which heates the exhost gases, and the engine therefore transfering some of this heat to the environment). Also, there are some mechanical energy loss due to vibrations and sound, which are also energy that comes from the fuel combustion.

5 0
3 years ago
A car speeds over a hill past point A, as shown in the figure. What is the maximum speed the car can have at point A such that i
Lubov Fominskaja [6]

Answer:

11.8 m/s

Explanation:

At the top of the hill, there are two forces on the car: weight force pulling down (towards the center of the circle), and normal force pushing up (away from the center of the circle).

Sum of forces in the centripetal direction:

∑F = ma

mg − N = m v²/r

At the maximum speed, the normal force is 0.

mg = m v²/r

g = v²/r

v = √(gr)

v = √(9.8 m/s² × 14.2 m)

v = 11.8 m/s

3 0
2 years ago
How far away is Earth from the Sun?
Snowcat [4.5K]
<span>d. 93 billion miles

</span>Earth, being the third planet from the sun is unique in the universe  because it is currently the only planet known to support life. Earth's distance from the sun is really one of  the key reasons why it is has widespread  life.Earth occupies what scientists sometimes call the Goldilocks zone. Its distance from the sun means its neither too hot nor too cold to support liquid water. Water is thought to be a key ingredient for life.<span> The energy from the sun in just the right intensity and the availability of water on the earth make it possible for life to thrive on earth. Plants use both these resources for photosynthesis and make nutrients that are available to support the life of animals on the earth. </span>
6 0
2 years ago
Read 2 more answers
Can someone give me an objective and subjective statement example please
shusha [124]

Answer:

Objective: It is raining. Subjective: I love the rain!

Explanation:

Anything objective sticks to the facts, but anything subjective has feelings. Objective and subjective are opposites.

(Hope this helps can I pls have brainlist (crown)☺️)

7 0
2 years ago
Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
DanielleElmas [232]

Answer:

Charge on each is 2 x 10⁻¹⁰.

Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

k = 9 x 10^9

r = 3.00 cm

= 0.03 m

q₁ = q₂

F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

q² = 4 x 10⁻²⁰

q = 2 x 10⁻¹⁰

As there is force of repulsion between the charges, the charges must be both positive or both negative.

3 0
3 years ago
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