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stealth61 [152]
3 years ago
10

A car moving with a velocity of 20 meters/second has 1.8**10^5 joules of kinetic energy what is the mass of the car?

Physics
1 answer:
Orlov [11]3 years ago
7 0
Kinetic energy = 1/2 x mass x velocity^2

mass = kinetic energy x 2 / velocity ^2

mass = (1.8 x 10^5) x 2/ 20^2

mass = 900 kg.
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A billiard ball is dropped from a height of 64 feet. Use the position function s(t) = –16???? 2 + ????0???? + ????0 to answer th
Delicious77 [7]

Answer:

s(t) = -16*t^2 + 64

v(t) = -32*t

a(t) = -32 ft/s^2

v(t) = 64 ft/s ... At impact

Explanation:

Given:-

- The height of the billiard ball t = 0 , h = 64 ft.

- The position function of an object under gravity is given by:

                                    s(t) = -16*t^2 + v_o*t + s_o

Find:-

a. Determine the position function s(t),

b. the velocity function v(t),

c. the acceleration function a(t).

d. What is the velocity of the ball at impact?

Solution:-

- To determine the position function we must initialize our problem and use the given general equation.

- s(t) is the position of the billiard ball from the ground at time t. So when t = 0, then s(t) = h. Hence, we have:

                                  s(t) = s_o = h = 64 ft

- Similarly we know that v_o is the initial velocity of the ball. Since, the ball was dropped we say that the initial velocity v_o = 0. Hence, the position of the ball from ground is given by following expression:

                                  s(t) = -16*t^2 + 64  

- To find the velocity expression v(t) we will take the time derivative of the position expression s(t) as follows:

                                  v(t) = d s(t) / dt

                                  v(t) = -16*2*t + 0

                                  v(t) = -32*t ft/s

- Similarly, the expression for acceleration a(t) is given by the time derivative of the velocity expression v(t) as follows:

                                  a(t) = d v(t) / dt

                                  a(t) = -32*t

                                  a(t) = -32 ft/s^2

- The velocity of ball at impact can be determined by evaluating s(t) = 0 and find the value for time t. Then that time t can be substituted in the velocity expression v(t) for final velocity. Or we could use the following 3rd kinematic equation as follows:

                                 v(t)^2 - 0^2 = 2*a(t)*s_o

                                 v(t)^2 = 2*(32)*(64)

                                 v(t) = 64 ft/s

- The ball has a velocity of 64 ft/s at impact!

6 0
3 years ago
Which answer is right? thanks if u help me! :)
enyata [817]

Answer:7.5 x 10* 14

Explanation:

7 0
3 years ago
Read 2 more answers
Physics!!! please help D:
Ugo [173]
Answer: A

Explanation: isotopes of the same thing element have the same number of protons in the nucleus but differ in the number of neutrons.
6 0
2 years ago
Suppose a 48-N sled is resting on packed snow. The coefficient of kinetic friction is 0.10. If a person weighing 660 N sits on t
Annette [7]

Assume the snow is uniform, and horizontal.

Given:

coefficient of kinetic friction = 0.10 = muK

weight of sled = 48 N

weight of rider = 660 N

normal force on of sled with rider = 48+660 N = 708 N = N

Force required to maintain a uniform speed

= coefficient of kinetic friction * normal force

= muK * N

= 0.10 * 708 N

=70.8 N


Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.


8 0
3 years ago
A car travels in a straight line for 5 h at a constant speed of 72 km/h. What is it’s acceleration
Luda [366]

Answer:

a \approx \: 0.001 \: m {s}^{ - 2}

Explanation:

Given:

initial \:  velocity \:  (u) = 0 \\  \\ Final  \: Velocity \:  (v) = 72 km /h   \\  \\ Time \:  (t) = 5 \:  hours \\  \\ Acceleration \:  (a) =?  \\  \\  \because \: a =  \frac{v - u}{t}  \\  \\  \therefore \: a =  \frac{72 - 0}{5}  \\  \\ a =  \frac{72}{5}  \\  \\ a = 14.5 \: km {h}^{ - 2}  \\  \\ a =  \frac{14.5 \times 1000}{3600\times 3600} \: m {s}^{ - 2}   \\  \\ a = 0.00111882716 \\  \\ a \approx \: 0.001 \: m {s}^{ - 2}

4 0
3 years ago
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