Answer:
Ohh .........................
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean
and standard error 
In this problem:
- 1,190 adults were asked, hence

- In fact 62% of all adults favor balancing the budget over cutting taxes, hence
.
The mean and the standard error are given by:


The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

By the Central Limit Theorem



has a p-value of 0.0166.
0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
<h3>
Answer: (C) (14,8)</h3>
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Explanation:
The perimeter of the square is 36, so each side length is 36/4 = 9 units.
Point B is located at (5,17). We move down 9 units to get to (5,8), which is the location of point A. Then we move 9 units to the right to arrive at (14,8) which is point D's location.
Or we could go from B = (5,17) to C = (14,17) and then to D = (14,8). Each time we move 9 units.
Answer:
Ratio of x-coordinates:




Ration of y-coordinates:




Step-by-step explanation:
The table is asking for the ratio of x-coordinates for each point (A, B, C and D) for both the image and pre-image. The ratio is the image 'x' or 'y' value ÷ the pre-image 'x' or 'y' value. Each ratio should be expressed in simplest form and should show the same pattern of dilation, or same scale factor. In this case, the second figure is 1/2 the size of the original figure.