The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. Given that Earth’s mass is 5.97 × 1024 kg and its radius i
2 answers:
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Answer:
t = 0.2845Nm (rounded to 4 decimal places)
Explanation:
The disk rotates at a distance of an arc length of 28cm
Arc length = radius × central angle × π/180
28cm = 10cm × central angle × π/180
Central angle = × 180/π ≈ 160.4°
Torque (t) = rFsin(central angle) , where F is the applied force
Radius in meters = 10/100 = 0.1m
t = 0.1m × 16N × sin160.4°
t = 0.2845Nm (rounded to 4 decimal places)
Answer:
Explanation:
The electric flux through a certain surface is given by (for a uniform field):
where:
E is the magnitude of the electric field
A is the area of the surface
is the angle between the direction of the field and of the normal to the surface
In this problem, we have:
is the electric field
L = 2.0 m is the side of the sheet, so the area is
, since the electric field is perpendicular to the surface
Therefore, the electric flux is
Answer:
The magnitude of the tangential velocity is
The magnitude of the resultant acceleration at that point is
Explanation:
From the question we are told that
The mass of the uniform disk is
The radius of the uniform disk is
The force applied on the disk is
Generally the angular speed i mathematically represented as
Where is the angular displacement given from the question as
is the angular acceleration which is mathematically represented as
The moment of inertial is mathematically represented as
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Considering the equation for angular acceleration
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Considering the equation for angular velocity
Substituting values
The tangential velocity of a given point on the rim is mathematically represented as
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The radial acceleration at hat point is mathematically represented as
The tangential acceleration at that point is mathematically represented as
Substituting values
The magnitude of resultant acceleration at that point is
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