Answer:
Given that
V2/V1= 0.25
And we know that in adiabatic process
TV^န-1= constant
So
T1/T2=( V1 /V2)^ န-1
So = ( 1/0.25)^ 0.66= 2.5
Also PV^န= constant
So P1/P2= (V2/V1)^န
= (1/0.25)^1.66 = 9.98
A. RMS speed is
Vrms= √ 3RT/M
But this is also
Vrms 2/Vrms1= (√T2/T1)
Vrms2=√2.5= 1.6vrms1
B.
Lambda=V/4π√2πr²N
So
Lambda 2/lambda 1= V2/V1 = 0.25
So the mean free path can be inferred to be 0.25 times the first mean free path
C. Using
Eth= 3/2KT
So Eth2/Eth1= T2/T1
So
Eth2= 2.5Eth1
D.
Using CV= 3/2R
Cvf= Cvi
So molar specific heat constant does not change
Given what we know, despite not having the figure attached to the question, we can still confirm that the magnitude for the acceleration of the dancer will be zero.
<h3>Why is the dancer's acceleration equal to zero?</h3>
This has to do with how the question clarifies the speed of the dancer. Though it does not give us an exact value, we are told that the speed is constant. This is an indicator that the acceleration is zero because with any other value for acceleration the speed <u>cannot remain</u> constant.
Therefore, given that any value for acceleration will increase or decrease the speed of the dancer, but we are told that the dancer's speed is constant throughout the trip, we can confirm that the magnitude for the acceleration of the dancer is zero.
To learn more about acceleration visit;
brainly.com/question/12134554?referrer=searchResults
Answer:
9.81N
Explanation:
the force of attraction is given by
F=<u>GmM</u><u>/</u><u>R²</u><u> </u>
where m is mass of the body
M is mass of the earth
R is radius of the earth
G is the universal gravitational constant(6.67x10-¹¹)
hence we substitute the values in the formula.
<em> </em><em>you</em><em> </em><em>can</em><em> </em><em>ask</em><em> </em><em>questions</em>
Answer:
5.972x10^27 x 10^-3 = 5.972x10^24
Explanation:
1g = 10^-3 kg => So the mass of Earth in kg is 5.972x10^24