Answer:
D.) reducing agent
Explanation:
Oxidized chemicals gain electrons. In order to gain these electrons, another chemical must lose electrons. So, the chemical (which will be oxidized) acts as a reducing agent, causing the other chemical to be reduced and lose electrons.
Potassium is placed where it is based on its properties and it's reactivity. It's also placed there based on it's atomic number.
Answer:
Explanation:
In the solution of AB , they are split to give ions as follows
AB ⇄ A⁺ + B⁻
Product of concentration of A⁺ and B⁻ in saturated solution of AB is constant .
This is called Ksp
Ksp = [A⁺] [ B⁻]
If product of concentration of A⁺ and B⁻ exceeds Ksp , the equilibrium shifts to the left side and excess ions come out of solution in the form of precipitate. So second option is the answer.
Answer:
V₂ = 317 L
Explanation:
Given data:
Initial number of moles of hydrogen = 18.9 mol
Initial volume of gas = 428 L
Final volume = ?
Final number of moles = 14.0 mol
Solution:
According to the Avogadro law,
Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.
Mathematical expression:
V₁/n₁ = V₂/n₂
V₁ = Initial Volume of balloon
n₁ = initial number of moles
V₂ = Final volume of balloon
n₂ = Final number of moles
Now we will put the values.
428 L / 18.9 mol = V₂/ 14 mol
V₂ =428 L × 14 mol / 18.9 mol
V₂ = 5992 L /18.9
V₂ = 317 L
Answer:
V₂ = 123.6 L
Explanation:
According to Boyle's law pressure and volume of a gas are inversely related if amount and temperature are kept constant. For the initial and final states the gas law is given as,
P₁ V₁ = P₂ V₂ ----- (1)
Data Given;
P₁ = 103 kPa
V₁ = 30 L
P₂ = 25 kPa
V₂ = ?
Solution:
Solving equation 1 for V₂,
V₂ = P₁ V₁ / P₂
Putting values,
V₂ = (103 kPa × 30 L) ÷ 25 kPa
V₂ = 123.6 L
Result:
As the pressure is decreased from 103 kPa to 25 kPa, therefore, volume has increased from 30 L to 123.6 L.
