Answer:
I hope 2 amperes of current passes
Answer:
c=0.14J/gC
Explanation:
A.
2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.
B.
We can use the expression for heat transmission

In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say

for water we have to
c = 4.18J / g ° C
replacing we have

I hope this is useful for you
A.
2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.
B.
Podemos usar la expresión para la transmisión de calor

En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir

para el agua tenemos que
c=4.18J/g°C
reemplazando tenemos

The speed of the car is exactly 150/7200 km/sec, or 125/6 meters/sec.
In more familiar units, that speed is equivalent to ...
-- (20 and 5/6) meters/sec
-- 75 km/hour
1) v = gt = 10*1.5 = 15 m/s
2) r = gt^2 /2 = 10*(1.5)^2 / 2 = 11.25 meters
The car is accelerating at 3 m/s² in the positive direction (to the right). By Newton's second law, the net force on the car in this direction is
∑ F = F[a] - F[f] - F[air] = ma
3100 N - 200 N - F[air] = (650 kg) (3 m/s²)
Solve for F[air] :
F[air] = 3100 N - 200 N - (650 kg) (3 m/s²)
F[air] = 3100 N - 200 N - 1950 N
F[air] = 950 N