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Naddika [18.5K]
3 years ago
12

Unlike mechanical waves such as sound or earthquake waves, EM waves can travel through empty space. True or false

Physics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

its true

Explanation:

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In order for fusion to begin during the birth of a star,there needs to be a certain amount of?
Anna007 [38]
I beleive the answer is b, charge 
6 0
3 years ago
A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]            ----------------------    (1)

in which R₁ is the resistance at temperature T₁

R_{T(2) is the resistance at temperature T₂

Given that V= IR

R = \frac{V}{I}

Therefore, the resistance at temperature 28°C is;

R_{28}= \frac{120V}{1.36A}

= 88.24Ω

R_{T(2) = \frac{120V}{1.23A}

= 97.56Ω

From (1) above;

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]      

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

\frac{0.1056}{4.5*10^{-4}}= T-28^0C

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

P= I^2_2R_{T^0C

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0
3 years ago
1. List one way mitosis and meiosis are the same and one way they are different.
kolbaska11 [484]
1. They both are same in the process, I mean they both are types of cell division they both form and give rise to new cells from the existing ones
difference would be in their division a mitotic cell gives rise to 2 cells where as a meiotic cell gives rise to 4.
2. the advantage of sexual reproduction is that , it produces genetic variation, disadvantage is it's a very slow process and takes lot of time
3. the advantage is that ,it's a very rapid process as it doesn't involve complex interactions. of genes and chromosomal recombination, the disadvantage would be is that they don't produce variation which can have adverse affect on their survival, even due to slightest change in the environment
4. Undergoing both the type of cell division is good as in human mitotic division is meant for growth and development whereas meiotic divisions are necessary and important for gametes formation and for raising new generation
6 0
3 years ago
An athlet starting from stationary moves with an acceleration 2.2m/s^2 for 5 seconds, then for other 5 seconds
ycow [4]

Answer:

The graph is shown below.

The athlete's speed at the finish line is 11 m/s

Total distance covered is 82.5 m.

Explanation:

The graph of speed versus time is drawn below.

Acceleration in the first 5 seconds, a=2.2 m/s²

From the graph, the slope of line OA is the acceleration in the first 5 seconds.

Slope of line OA is given as:

slope, a=\frac{AD}{OD}\\2.2=\frac{AD}{5}\\AD =2.2\times 5=11\textrm{ m/s}

Now, the length AD is nothing but speed at point A or B as AB is a straight line.

Therefore, the speed when crossing the finish line is the speed at B which is equal to 11 m/s.

Distance covered is given by the total area under the graph.

The total area can be divided into two shapes; a triangle and a rectangle.

The area under the graph is the sum of areas of triangle OAD and rectangle ABCD.

Area of triangle OAD is, A_{tri}=\frac{1}{2}\times OD\times AD=\frac{1}{2}\times 5\times 11=27.5

Area of rectangle ABCD is, A_{rec}=AB\times AD=5\times 11=55

Therefore, the total distance covered till the finish line is given as:

d_{total}=27.5+55=82.5\textrm{ m}

4 0
3 years ago
Materials that are poor conductors of thermal energy are called.....
Anettt [7]
First one, insulator. Second one, conductor.
5 0
3 years ago
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