Answer:
- The magnitude of the vector
is 107.76 m
Explanation:
To find the components of the vectors we can use:
where 
is the magnitude of the vector, and θ is the angle over the positive x axis.
The negative x axis is displaced 180 ° over the positive x axis, so, we can take:
Now, we can perform vector addition. Taking two vectors, the vector addition is performed:
So, for our vectors:
To find the magnitude of this vector, we can use the Pythagorean Theorem
And this is the magnitude we are looking for.
I believe all of these would be known as specific phobias.
Answer:
t = 1.41 sec.
Explanation:
If we assume that the acceleration of the blocks is constant, we can apply any of the kinematic equations to get the time since the block 2 was released till it reached the floor.
First, we need to find the value of acceleration, which is the same for both blocks.
If we take as our system both blocks, and think about the pulley as redirecting the force simply (as tension in the strings behave like internal forces) , we can apply Newton's 2nd Law, as they were moving along the same axis, aiming at opposite directions, as follows:
F = m₂*g - m₁*g = (m₁+m₂)*a (we choose as positive the direction of the acceleration, will be the one defined by the larger mass, in this case m₂)
⇒ a = (
= g/5 m/s²
Once we got the value of a, we can use for instance this kinematic equation, and solve for t:
Δx = 1/2*a*t² ⇒ t² = (2* 1.96m *5)/g = 2 sec² ⇒ t = √2 = 1.41 sec.
Answer:
add text fully or atleast add book name edition . solution is in picture. chk pictures ignore b part
Explanation:
To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.
The tension in the vertical plane will be equivalent to the centripetal force therefore
Here,
m = mass
v = Velocity
r = Radius
The tension in the horizontal plane will be subject to the action of the weight, therefore
Matching both expressions with respect to the tension we will have to
Then we have that,
Rearranging to find the velocity we have that
The value of the angle is 14.5°, the acceleration (g) is 9.8m/s^2 and the radius is
Replacing we have that
Therefore the speed of each seat is 4.492m/s
