<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate?
</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
Answer:
Solubility
Explanation:
Material becomes soluble in solvent and disappears.
Explanation:
mass of student(M1)=55
mass of book(M2)=?
distance(d)=0.435m
gravitational constant (G)=6.67×10^-11
force(F)=2.68×10^-8
Now,
F=GM1M2/d^2.
then do the numericals .It's taking long time so I escaped Sorry
Answer:
The charge flows through a point in the circuit during the change is 0.044 C.
Explanation:
Given that,
Number of turns in the copper wire, N = 200
Area of cross section, 
Resistance of the circuit, R = 118 ohms
If an externally applied uniform longitudinal magnetic filed in the core changes from 1.65 T in one direction to 1.65 T in the opposite direction.
We need to find the charge flows through a point in the circuit during the change. Due to change in magnetic field an emf is induced in it. It is given by :

Using Ohm's law :


Electric current is equal to the rate of change of electric charge. So,

So, the charge flows through a point in the circuit during the change is 0.044 C.
Too much skepticism will lead one to doubt everything while too little will lead to gullibility.