Answer:
10m/s^2
Explanation:
Given data
velocity= 40m/s
time= 4 seconds
Acceleration a =????
We know that
a= velocity/time
substitute
a=40/4
a= 10m/s^2
Hence the acceleration will be 10m/s^2
Answer:
The magnitude of the net electric field is:

Explanation:
The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).
On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).
Knowing this, the <u>magnitude of the net electric</u> field will be the<u> E1 + E2. </u>
Let's find first E1 and E2.
The electric field equation is given by:

Where:
- k is the Coulomb constant (k = 9*10^{9} Nm²/C²)
- q1 is the first charge
- d1 is the distance from q1 to P


And E2 will be:



Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.



I hope it helps you!
337493603.8m/s²
Explanation:
Radius of the earth = 6.38 x 10¹⁶m
time = 24hr (86400s)
Unknown:
Centripetal acceleration = ?
Solution:
The centripetal acceleration is directed inward to keep the body from falling off the surface of the earth.
centripetal acceleration = 
where v is the velocity and r is the radius
also;
v = wr
where w is the angular velocity
substituting in the equation for centripetal acceleration gives;
a = w²r
also w = 
therefore;
a = 
a = 
a = 337493603.8m/s²
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Acceleration brainly.com/question/3820012
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Answer:
M[min] = M[basket+people+ balloon, not gas] * ΔR/R[b]
ΔR is the difference in density between the gas inside and surrounding the balloon.
R[b] is the density of gas inside the baloon.
====================================
Let V be the volume of helium required.
Upthrust on helium = Weight of the volume of air displaced = Density of air * g * Volume of helium = 1.225 * g * V
U = 1.225gV newtons
----
Weight of Helium = Volume of Helium * Density of Helium * g
W[h] = 0.18gV N
Net Upward force produced by helium, F = Upthrust - Weight = (1.225-0.18) gV = 1.045gV N -----
Weight of 260kg = 2549.7 N
Then to lift the whole thing, F > 2549.7
So minimal F would be 2549.7
----
1.045gV = 2549.7
V = 248.8 m^3
Mass of helium required = V * Density of Helium = 248.8 * 0.18 = 44.8kg (3sf)
=====
Let the density of the surroundings be R
Then U-W = (1-0.9)RgV = 0.1RgV
So 0.1RgV = 2549.7 N
V = 2549.7 / 0.1Rg
Assuming that R is again 1.255, V = 2071.7 m^3
Then mass of hot air required = 230.2 * 0.9R = 2340 kg
Notice from this that M = 2549.7/0.9Rg * 0.1R so
M[min] = Weight of basket * (difference in density between balloon's gas and surroundings / density of gas in balloon)
M[min] = M[basket] * ΔR/R[b]