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hammer [34]
3 years ago
6

What hazardous wastes are common in ordinary households? What can you do to reduce the impact you make on the environment from t

he use of hazardous wastes?
Physics
1 answer:
labwork [276]3 years ago
3 0

Answer:

The most common products include aerosols, anti-freeze, asbestos, fertilizers, motor oil, paint supplies, photo chemicals, poisons, and solvents, cleaning supplies.

Explanation:

Use homemade cleaners

You can find local retailers to take rechargeable batteries from laptop computers, cordless power tools, cellular and cordless phones, and camcorders at the Rechargeable Battery Recycling Corporation’s website

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A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope
serious [3.7K]
<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? 

</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
7 0
3 years ago
Serena is mixing a material into a beaker filled with a liquid. She notices that the material seems to disappear into the liquid
xxMikexx [17]

Answer:

Solubility

Explanation:

Material becomes soluble in solvent and disappears.

5 0
3 years ago
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A 55.0 kg student feels a
natta225 [31]

Explanation:

mass of student(M1)=55

mass of book(M2)=?

distance(d)=0.435m

gravitational constant (G)=6.67×10^-11

force(F)=2.68×10^-8

Now,

F=GM1M2/d^2.

then do the numericals .It's taking long time so I escaped Sorry

5 0
3 years ago
Two hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.20 × 10−3 m2
Novosadov [1.4K]

Answer:

The charge flows through a point in the circuit during the change is 0.044 C.

Explanation:

Given that,

Number of turns in the copper wire, N = 200

Area of cross section, A=1.2\times 10^{-3}\ m^2

Resistance of the circuit, R = 118 ohms

If an externally applied uniform longitudinal magnetic filed in the core changes from 1.65 T in one direction to 1.65 T in the opposite direction.

We need to find the charge flows through a point in the circuit during the change. Due to change in magnetic field an emf is induced in it. It is given by :

\epsilon=\dfrac{d\phi}{dt}

Using Ohm's law :

\epsilon=IR

IR=-\dfrac{d\phi}{dt}\\\\I=-\dfrac{1}{R}\dfrac{d\phi}{dt}

Electric current is equal to the rate of change of electric charge. So,

dq=\dfrac{NA(B(0)-B(t))}{R}\\\\dq=\dfrac{200\times 1.2\times 10^{-3}(1.65+1.65)}{18}\\\\dq=0.044\ C

So, the charge flows through a point in the circuit during the change is 0.044 C.

4 0
3 years ago
Too much skepticism can
Schach [20]
Too much skepticism will lead one to doubt everything while too little will lead to gullibility. 
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