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zavuch27 [327]
2 years ago
10

Trong chân không khi hai điện tích cách nhau lần lượt là d và d+10cm thì lực tương tác điện giữa chúng có độ lớn tương ứng là 2.

0-6 N và 5.10-7 N tính giá trị của d
Physics
1 answer:
Cerrena [4.2K]2 years ago
5 0

Answer:

H2O is also known as for water

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A box is moving along the x-axis and its position varies in time according to the expression:
Colt1911 [192]

Answer:

38.4 m/s

Explanation:

a) at t = 3.2s. x = 6 * 3.2^2 = 61.44 m

b) at t = 3.2 + Δt. x = 6*(3.2 + \Delta t)^2

c) As Δt approaches 0. We can find the velocity by the ratio of Δx/Δt

v = \frac{\Delta x}{\Delta t} = \frac{x_2 - x_1}{\Delta t}

v = \frac{6*(3.2 + \Delta t)^2 - 61.44}{\Delta t}

v = \frac{6(3.2^2 + 6.4\Delta t + \Delta t^2) - 61.44}{\Delta t}

v = \frac{61.44 + 38.4\Delta t + \Delta t^2 - 61.44}{\Delta t}

v = \frac{\Delta t(38.4 + \Delta t)}{\Delta t}

v = 38.4 + \Delta t

As Δt approaches 0, v = 38.4 + 0 = 38.4 m/s

3 0
3 years ago
A person throws a ball straight up. He releases the ball at a height of 1.75 m above the ground and with a velocity of 12.0 m/s.
Lyrx [107]

Answer:

a) 1.22 s

b) 9.089 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-12}{-9.81}\\\Rightarrow t=1.22\ s

Time taken by the ball to reach the highest point is 1.22 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=12\times 1.22+\frac{1}{2}\times -9.81\times 1.22^2\\\Rightarrow s=7.339\ m

The maximum height the ball will reach above the ground is 1.75+7.339 = 9.089 m

8 0
3 years ago
I need help with these four problems.. anyone??
babunello [35]
1) 14g
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Reptile [31]

Answer:

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Explanation:

to get the answer of a and b

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A person will feel weightless whenever?
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When your'e in space you feel weightless blc there's no grsvity in space.
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