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ivolga24 [154]
3 years ago
12

A car traveling north with a velocity of 33 m/sec slows down to a velocity of 12 m/sec north within 10 sec. What is the car’s de

celeration?
Physics
2 answers:
Alja [10]3 years ago
6 0
33 m/s north is initial velocity (Vi). 12 m/s north is final velocity (Vf). 10s is the time. The equation for acceleration is Vf-Vi/t. 12-33 is -21. -21 divided by 10 is -2.1. The answer is -2.1 m/s^2 North.
strojnjashka [21]3 years ago
4 0

a=v/t

v= 33-12 = 21

21÷10=2.1

a= 2.1

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Explanation:

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(you can try it at home)

It is related to the temperature of the gas.

5 0
3 years ago
If =12a andthe distance from each wire to point p is 0.12m, then what is the magnitude of the magnetic force per unit length on
vaieri [72.5K]

The magnitude of the magnetic force per unit length on the top wire is

2×10⁻⁵  N/m

<h3>How can we calculate the magnitude of the magnetic force per unit length on the top wire ?</h3>

To calculate the magnitude of the magnetic force per unit length on the top wire, we are using the formula

F= \frac{\mu_0 I_f}{2\pi d}

Here we are given,

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From the above calculation, we can conclude that the magnitude of the magnetic force per unit length on the top wire is 2×10⁻⁵ N/m.

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7 0
2 years ago
"determine the average velocity of the particle over the time interval"
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This link should help you out https://quizlet.com/40330134/biomechanics-questions-flash-cards/

5 0
4 years ago
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6 0
3 years ago
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natali 33 [55]

Answer:

Relative humidity %

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