Answer:
y = 0m
y0 = 166m
v0y = 0 m/s
g = 9.8 m/s^2
t = ?
Solve for t:
y = y0 + v0y*t - (0.5)gt^2
0 = 166 - (0.5)(9.8)t^2
t = 5.82 s
Now, using time, we can solve for the range using the equation:
x = vx(t)
x = (40)(5.82)
x = 232.8 m
The impact horizontal component of velocity will be 40 m/s as velocity in terms of x is always constant. To find the impact vertical component of velocity, we use the equation:
v = v0y - gt
v = 0 - (9.8)(5.82)
v = -57.04 m/s
To solve this problem it is necessary to apply the trigonometric ratios of the given velocity components.
If we make a graph of the velocity vectors in their respective velocities according to the given description we will have something similar to the attached graph.
The angle could be obtained from the components of the opposite leg and the adjacent leg so that
The opposite leg value (y) is 40cm / s and the adjacent leg (x) is 30cm / s
Therefore the final direction that does the first ball is 36.87°
Answer:
a. 1.75 Nm²/C
b. Yes.
Explanation:
a. Electric Flux is given as:
Φ = E*A*cosθ
Where E = electric flux
A = Surface area
Φ = 14 * 0.25 * cos60
Φ = 1.75 Nm²/C
b. Yes, the shape of the sheet will affect the Flux through it. This is because flux is dependent on area of the surface and the area is dependent on the shape of the surface.
Answer:
Surface tension is the result of water molecules pulling inward with a strong attractive force. This attractive force brings the molecules on the surface of the water close together and causes the surface of the water to be drawn toward the water molecules beneath the surface. Since there are no water molecules above the surface, there are uneven forces. This causes surface tension, allowing the coin to float on the water’s surface.
Explanation:
Brainliest pls
Answer: y(t)= 1/π^2 sin(6*π^2*t)
Explanation: In order to solve this problem we have to consider the general expression for a harmonic movement given by:
y(t)= A*sin (ω*t +φo) where ω is the angular frequency. A is the amplitude.
The data are: ν= 3π; y(t=0)=0 and y'(0)=6.
Firstly we know that 2πν=ω then ω=6*π^2
Then, we have y(0)=0=A*sin (6*π^2*0+φo)= A sin (φo)=0 then φo=0
Besides y'(t)=6*π^2*A*cos (6*π^2*t)
y'(0)=6=6*π^2*A*cos (6*π^2*0)
6=6*π^2*A then A= 1/π^2
Finally the equation is:
y(t)= 1/π^2 sin(6*π^2*t)
