<span>Answer:
The dilution formula is V1M1 = V2M2.
We need 3 of the values to calculate the 4th.
We have the original volume (2 mL of copper ion solution) and the final volume (20 mL), but we don't have the concentration of either the original or the final copper solution,
All we can say is the resulting solution is 10 times as dilute as the original was-
V1M1 = V2M2
2Ă—0.200 = 20Ă—M2, so M2 = 0.400/20 = 0.020M</span>
If you search the question text (starting with "Write") you will definitely find the answer
Hello!
When HI is added, the buffer reacts in the following way:
1) Neutralizing of the Acid:
HI + NH₄OH → NH₄I + H₂O
2) Dissociation of the salt of a weak acid:
NH₄I → NH₄⁺(aq) + I⁻ (aq)
3) Dissociation of a weak acid to form H₃O⁺ (very little):
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.
Have a nice day!
The graph would not have plummeted if various species were planted due to improvement of the potato crops.
<h3>What is variety?</h3>
The term variety has to do with the planting of different species of plants on the same farm. We know that the planting of different species of the same crop helps to improve the resistance to diseases of a plant.
Hence, the graph would not have plummeted if various species were planted due to improvement of the potato crops.
Learn more about improved specie:brainly.com/question/3627477
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First determine the molality of the solution. m = (w solute)/[(mm solute)(kg solvent)] -- mm means molar mass. So,
m = (14.7 g)/[(180 g/mol)(0.150 kg) =0.544 mol/kg = 0.544 m
Change in boiling point (∆t) = m x Kbp = (0.544 m)(0.512 °C/m) = 0.28°C
The solution will boil at 100.28°C at 1 atm.
the density if water is 1.00 g/ml and Kb= 0.512 C/m
