Answer:
f = 2858.33 Hz
Explanation:
given,
distance between speaker (A) and the person = 2.34 m
Distance between speaker (B) and the person is AB =
=
= 2.46 m
path difference d = BP - AP
= 2.46 - 2.34 m
= 0.12 m
now, λ = 0.12
speed of sound = 343 m/s


f = 2858.33 Hz
the lowest frequency that will produce constructive interference is equal to
f = 2858.33 Hz
The speed at which a wave of frequency of 14 Hz and a wavelength of 3 m will travel is 42 m / s
v = λ / T
f = 1 / T
v = f λ
v = Wave speed
λ = Wavelength
T = Time period
f = Frequency
f = 14 Hz
λ = 3 m
v = 14 * 3
v = 42 m / s
Frequency is the number of time an event occurs repeatedly in an unit amount of time. Its unit is hertz which in terms of SI unit is
.
Therefore, the speed at which the wave will travel is 42 m / s
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Answer:
proton and neutron has the same mass of 1amu
Answer: The Propellant fraction is 0.87.
The payload fraction is 0.04.
Δv = 8991.81 m/s
Explanation: To determine the fractions, first, calculate the total mass of the rocket:



The Propellant Fraction will be


0.87
The Payload Fraction is:


0.04
The value of Δv is calculated by the formula:
Δv = 
The exhaust velocity (
) is:

9.81*450
4414.5
is the total mass after the rocket consume all the propellant and
is the total mass before the action.
Δv = 
Δv = 
Δv = - 4414.5.ln(0.13)
Δv = 8991.81
Δv will be 8991.81 m/s.