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3 years ago

Rank the following in terms of increasing inertia:

Physics

2 answers:

Naddik [55]3 years ago

7 0

C. A 1200kg car is going 15m/s

gavmur [86]3 years ago

4 0

Answer:

Increasing order of inertia is as following

d) < b) < c) < a)

Explanation:

Inertia is the property of mass. We define inertia as the property of mass due to which a given mass will will resist any change in it state of motion.

So if an object will have more mass then it is more difficult to change the state of motion of that type of object.

So here we have

a). A 10,000 kg train car at rest

b). A 100 kg person running at 5 m/s

c). A 1200 kg car going 15 m/s

d). A 15 kg meteor going at a speed of 1000 m/s

Now for arranging increasing order of inertia we need to arrange them in increasing order of their mass

d) < b) < c) < a)

So above is the increasing order of inertia

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Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t

Ksenya-84 [330]

Change in velocity of larger moose: (1/3)v - v = -(2/3)v
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
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4 0

3 years ago

Read 2 more answers

How do I go about this?

Anna71 [15]

Hi there!

(a)

Recall that:
$W = F \cdot d = Fdcos\theta$

W = Work (J)
F = Force (N)
d = Displacement (m)

Since this is a dot product, we only use the component of force that is IN the direction of the displacement. We can use the horizontal component of the given force to solve for the work.

$W =248(56)cos(30) = 12027.36 J$

To the nearest multiple of ten:
$W_A = \boxed{12030 J}$

(b)
The object is not being displaced vertically. Since the displacement (horizontal) is perpendicular to the force of gravity (vertical), cos(90°) = 0, and there is NO work done by gravity.

Thus:
$\boxed{W_g = 0 J}$

(d)

Recall that the force of kinetic friction is given by:
$F_{f} =\mu_k mg$

Since the force of friction resists the applied force (assigned the positive direction), the work due to friction is NEGATIVE because energy is being LOST. Thus:
$W_f = -\mu_k mgd\\W_f = - (0.1)(56)(9.8)(56) = -3073.28 J$

In multiples of ten:
$\boxed{W_f = -3070 J}$

(e)
Simply add up the above values of work to find the net work.

$W_{net} = W_A + W_f \\\\W_{net} = 12027.36 + (-3073.28) = 8954.08 J$

Nearest multiple of ten:
$\boxed{W_{net} = 8950 J}}$

(f)
Similarly, we can use a summation of forces in the HORIZONTAL direction. (cosine of the applied force)
$F_{net} = F_{Ax} - F_f$

$W = F_{net} \cdot d = (F_{Ax} - F_f)$

$W = (F_Acos(30) - \mu_k mg)d\\W = (248cos(30) - 0.1(56)(9.8)) * 56 \\\\W = 8954.08 J$

Nearest multiple of ten:
$\boxed{W_{net} = 8950 J}$

5 0

2 years ago

A runner with a mass of 80kg accelerates from 0 to 9 m/s in 3 s find the net force

frosja888 [35]

So, first you find your acceleration which is 3m/s^2, using the acceleration formula.
Now set up your equation, F=ma, so put in the stuff, F=80kg·3m/s^2. Then solve your equation by multiplying, and you get F=240N, since newtons are your measurement.
Hope this helps

4 0

3 years ago

If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th

Trava [24]

Answer:

- path differnce = 2.18*10^-6

- 1538 lines

Explanation:

- The path difference for the waves that produce the pattern of diffraction, is given by the following formula:

$path\ difference\ = dsin\theta$ (1)