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3 years ago

14

When light propagates from a material with a given index of refraction into a material with a smaller index of refraction, the s

peed of the light
A) incease
B) decrease
C) remain constant

1 answer:

SSSSS [86.1K]3 years ago

7 0

Answer: A) increase

Explanation:

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A 4.00 µf capacitor is connected to a 12.0 v battery.

atroni [7]

(a) The capacitance of the capacitor is:
$C=4 \mu F=4 \cdot 10^{-6}F$
and the voltage applied across its plates is
$V=12.0 V$

The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
$C= \frac{Q}{V}$
and re-arranging it we find the charge stored in the capacitor:
$Q=CV=(4 \cdot 10^{-6} F)(12.0 V)=4.8 \cdot 10^{-5} C$

(b) The electrical potential energy stored in a capacitor is given by
$U= \frac{1}{2}CV^2$
where C is the capacitance and V is the voltage. The new voltage is
$V=1.50 V$
so the energy stored in the capacitor is
$U= \frac{1}{2}(4 \cdot 10^{-6} F)(1.50 V)^2=4.5 \cdot 10^{-6} J$

3 0

3 years ago

Read 2 more answers

A jogger moves from a position x =

vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0

3 years ago

Which is the smallest unit of life?

emmasim [6.3K]

Answer:

the cell is the smallest unit

7 0

2 years ago

Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field

Xelga [282]

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

$B = \mu_{0}nI$

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

$B_{1} = \mu_{0}n_{1}I ------------------- equation 1$

For Solenoid 2:

n₂ = 6n₁

Therefore,

$B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2$

Diving equation 1 and equation 2:

$\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6$

Hence, the correct option is:

<u>6</u>

8 0

3 years ago

16) The depth of pond is ....... if it seems to be 10m a) 10m b) 7.7m c) 13.3m d) 20m

Alexxandr [17]

The answer is d) 20 m.

The depth of pond is 20 m if it seems to be 10 m.

The formula relating real depth and app. depth :

$\boxed {A = \frac{R}{n}}}$

In this case, refractive index has to be an whole number for real depth to give a whole number for app. depth.

Then, real depth must be a multiple of 10, but refractive index cannot be 1
The option is 20 m

7 0

2 years ago