Acceleration is the rate at which an object changes its speed. When a raindrop is falling down from the clouds due to gravity, the veloicty is pretty much fast, however air resistance comes in action and slows the droplet down... it gives it a constant speed until it hits the ground
Balanced equation = 2 NaHCO3 —-> Na2CO3 + H2O + CO2
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Sorry I skate and usually the smaller wheel rolls faster. Try C. then It's like longboard wheels they roll pretty fast.
Answer:
0.0119
Explanation:
There was a part missing. I think this is the whole question:
<em>Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?</em>
A (aq) ⇌ 2B (aq) + C(aq)
<em>Remember to use correct significant figures in your answer. Do not include units in your response.</em>
First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.
A (aq) ⇌ 2B (aq) + C (aq)
I 0.0510 0 0
C -x +2x +x
E 0.0510-x 2x x
Since the concentration at equilibrium of A is 0.0153 M, we get

We can use the value of x to calculate the concentrations at equilibrium.
![[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\](https://tex.z-dn.net/?f=%5BA%5De%20%3D%200.0153%20M%20%5C%5C%5BB%5De%20%3D%202x%20%3D%202%280.0357%29%20%3D%200.0714%20M%20%5C%5C%5BC%5De%20%3D%20x%20%3D%200.0357%20M%20%5C%5C)
The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.
![Kc = \frac{[B]^{2} \times [C]}{[A]} = \frac{0.0714^{2} \times 0.0357}{0.0153} = 0.0119](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BB%5D%5E%7B2%7D%20%20%5Ctimes%20%5BC%5D%7D%7B%5BA%5D%7D%20%3D%20%5Cfrac%7B0.0714%5E%7B2%7D%20%20%5Ctimes%200.0357%7D%7B0.0153%7D%20%3D%200.0119)
The equilibrium constant for this reaction at equilibrium is 0.0119.
You can learn more about equilibrium here: brainly.com/question/4289021
The mass of NCl3 in 4.00 moles of NCl3 is 481.44 grams
Mole is defined as the amount of the substance containing the same number of discrete entities (atoms, molecules, ions, etc) as there are atoms in a sample of pure 12C weighing exactly 12g. The number of particles present in one mole of any substance =Avogadro Number=6.
The formula for number mole is given as:
Number of moles = <u>Mass of the substance </u> ; Now substituting the values
Molar mass
⇒ 4.00 = <u>x </u> [Molar mass of NCl3 = 120.36]
120.36
⇒ x = 4.00 × 120.36
⇒ x = 481.44 grams
Therefore the mass of NCl3 is 481.44 grams
To know more about mole concept
brainly.com/question/23059935
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