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Nataly_w [17]
2 years ago
13

For group 1a metals, which electron is the most difficult to remove?

Chemistry
1 answer:
shtirl [24]2 years ago
4 0

The periodic table contains groups and periods that include the elements. For group 1 metal lithium is least likely to lose an electron.

<h3>What are group 1 metals?</h3>

Group 1 metals are the alkali metals that include, Li, Na, K, Rb, and Cs. They show the property exhibited by the metals. The chemical trends of group 1 show that cesium loses an electron more easily than the other elements.

When going down the group the tendency to lose electrons increases as the atomic radius increases. The electron gets far away from the nucleus making it easy to get removed.

Therefore, lithium being the first element of the group has the smallest radii and is least likely to lose an electron.

Learn more about the group I metals here:

brainly.com/question/27187436

#SPJ4

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Solid lithium iodide decomposes into solid lithium and iodine gas . Write a balanced chemical equation for this reaction.
olga nikolaevna [1]
\text{2LiI(s)}\rightarrow \text{2Li(s)+}\text{I}_{2}\text{(s)}
3 0
3 years ago
Read 2 more answers
The number of moles in 75.0 liters of F2 at STP
GalinKa [24]
What is the question?
7 0
3 years ago
Please help and explain how to get the answer!
zzz [600]

Answer 1: The correct answer is option (B)

Answer 2: The correct answer is option (B)

Explanation 1:

2Na+Cl_2\rightarrow 2NaCl

moles of NaCl = \frac{\text{given mass of NaCl}}{\text{molar mass of NaCl}}=\frac{200 g}{58.5 g/mol}=3.4188 mol

According to reaction, 2 moles NaCl are obtained from 2 moles of Na, then 3.4188 moles of NaCl are obtained from: \frac{1}{1}\times 3.4188 moles of Na.

Mass of Na = moles of sodium × Molar mass of sodium

=23 g/mol\times 3.4188 mol=78.632 g

From the given option nearest answer to calculated answer is option (B) that is 78.65 g.

Explanation 2:

2K+2H_2O\rightarrow 2KOH+H_2

moles of potassium(K)= \frac{\text{given mass of K}}{\text{molar mass of K}}=\frac{23.5 g}{39 g/mol}=0.6025 mol

According to reaction, 2 moles of K gives 2 moles of KOH , then 0.6025 moles of K will give : \frac{1}{1}\times 0.6025 moles of KOH

Mass of KOH = moles of KOH × Molar mass of KOH

0.6025 mol\times 56 g/mol=33.74 g\approx 33.7 g

From the given option nearest answer to calculated answer is option (A) that 33.7 g.

6 0
3 years ago
Calculeaza cantitatea de solutie de clorura de sodiu cu concentratia 30% necesara pentru obtinerea a 112 L de clor (c.n). Ce vol
Slav-nsk [51]

Answer:

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Explanation:

7 0
3 years ago
If a gas is cooled from 425.0K to 275.15K and the volume is kept constant what final pressure would result if the original press
mr Goodwill [35]

Answer: 498.51mmHg

Explanation:

First let us analyse what was given from the question:

T1 = 425K

T2 = 275.15K

P1 = 770 mmHg

P2 =?

Using the general gas equation

P1V1/T1 = P2V2/T2

But we were told from the question that the volume is constant. So, our equation becomes:

P1/T1 = P2/T2

770/425 = P2 /275.15

Cross multiply to express in linear form:

P2 x 425 = 770 x 275.15

Divide both side by 425, we have:

P2 = (770 x 275.15) /425

P2 = 498.51mmHg

4 0
3 years ago
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