Nucleic acids, proteins, carbohydrates, and lipids are the four major types of biomolecules that form all living things. These biomolecules consists of monomers linked together by covalent bonds to form polymers.
- Nucleic acids, proteins, carbohydrates and lipids can be classified according to their basic elements, monomer constituents, and functions.
Basic elements:
- Nucleic acids: Hydrogen (H); Carbon (C); Oxygen (O); Nitrogen (N); Phosphorous (P)
- Proteins: Hydrogen (H); Carbon (C); Oxygen (O); Nitrogen (N); Sulfur (Z)
- Carbohydrates: Hydrogen (H); Carbon (C); Oxygen (O)
- Lipids: Hydrogen (H); Carbon (C); Oxygen (O); Phosphorous (P)
Monomer constituents:
- Nucleic acids: nucleotides
- Proteins: amino acids
- Carbohydrates: monosaccharides
- Lipids: fatty acids and glycerol
Functions:
- Nucleic acids: contains the hereditary information to synthesize proteins
- Proteins: regulate metabolic processes (enzymes), the main biomolecule of cellular structures
- Carbohydrates: store energy (short term); form cellular structures
- Lipids: store energy (long term); the main component of biological membranes
Examples:
- Nucleic acids: DNA and RNA
- Proteins: lactase; collagen
- Carbohydrates: starch (polysaccharide); glucose (monosacharide)
- Lipids: phospholipids; cholesterol
Learn more in:
brainly.com/question/736132?referrer=searchResults
The three grains are rice, wheat, and corn
Rice is the main grain used in places such as Asia ans SEA, corn is mostly used in the Americas, while wheat is mostly found in European countries.
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
The right answers are B, C and D.
An enzyme is a protein with catalytic properties. Virtually all biomolecules capable of catalyzing chemical reactions in cells are enzymes; some catalytic biomolecules, however, consist of RNA and are therefore distinct enzymes: they are ribozymes.
An enzyme acts by lowering the activation energy of a chemical reaction, which increases the rate of reaction.
