I think the answer is D, ride comfort. This is something that doesn't necessarily change between EVs and internal combustion vehicles, but is more up to the company itself and I don't think it would really be considered a benefit nor do anything for the environment
Answer:
The object will have an upward acceleration
Explanation:
Let's consider the forces applied on the box. We have only two forces:
- The applied force of push, 
, downward
- The force of gravity, 
, (also known as weight of the object), downward
Therefore, the net force on the box is:
Here, we know that force applied is equal or greater than the weight, so
And therefore the net force is greater than zero:
(1)
According to Newton's second law of motion, the net force on the box is equal to the product between its mass and its acceleration:
where
m is the mass of the box
a is its acceleration
Given (1), this means that
Therefore, the box will have an upward acceleration.
In this case force example we have:
So the mass of the box is
So the net force is
And the acceleration is
There's supposed to be a blank in the statement, where the answer is supposed to be inserted.
The question is supposed to say: "A wave is a disturbance that carries ______ from one place to another through matter or space".
To answer the question, write the word "<em>energy</em>" in the blank.
(a) The ball's height <em>y</em> at time <em>t</em> is given by
<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :
0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²
0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )
<em>t</em> = 0 or (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0
The first time refers to where the ball is initially launched, so we omit that solution.
(20 m/s) sin(40º) = 1/2 <em>g t</em>
<em>t</em> = (40 m/s) sin(40º) / <em>g</em>
<em>t</em> ≈ 2.6 s
(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So
0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>
where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :
<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)
<em>y</em> ≈ 8.4 m
