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QveST [7]
3 years ago
12

NADH and FADH 2 are important in cellular respiration because they deliver high-energy electrons to the electron transport syste

m. Electron transport produces _____ ATP molecule(s) per NADH molecule and _____ ATP molecules(s) perFADH 2 molecule.
Chemistry
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

Electron transport produces 3 ATP molecule(s) per NADH molecule and 2 ATP molecules(s) perFADH 2 molecule.

Explanation:

The mechanism by which ATP is produced is explained by the theory of chemosmotic coupling.

This theory establishes that the synthesis of ATP in cellular respiration comes from an electrochemical gradient existing between the internal membrane and the space of the intermembrane of the mitochondria, through the use of the energy of NADH and FADH2 that have been formed by the rupture of molecules rich in energy, such as glucose.

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!DUE SOON PLEASE HELP!
nalin [4]

Answer:

balanced;

unbalanced;

unbalanced;

balanced;

Explanation:

CaO + 3C → CaC2 + CO  //all elements are balanced

Na + H2O → 2NaOH + H2  //Na is not balanced on the left

4Fe + O2 → 2Fe2O3  //O is not balanced on the left

2Mg + O2 → 2MgO //left is equal to right, balanced

6 0
3 years ago
Identify the parts of the atom that are labeled in the diagram
baherus [9]

Answer:

A- Nucleus

B-Energy levels

Explanation:

  • An atom refers to the smallest particle of an element that can take part in a chemical reaction.
  • An atom is made up of two major parts namely; the nucleus and the energy shell or energy levels.
  • The nucleus of an atom contains the sub atomic particles, protons and neutrons while the energy shells contain the sub atomic particle electrons.
  • It is important to note that the protons in the nucleus are positively charged which makes the nucleus to be positively charged.
  • On the other hand, energy shells are negatively charged because of the negative charge of the electrons.
6 0
3 years ago
Read 2 more answers
The reaction can be described using the equation: 2C2H25O24CO22H2O. How much C2H2is needed to react with 68.1 g of O2to produce
Sophie [7]

Answer:

22.13g

Explanation:

We'll begin by writing a balanced equation for the reaction. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Next, we'll calculate the mass of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of C2H2 = (12x2) + (2x1)

= 24 + 2 = 26g/mol

Mass of C2H2 that reacted from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 that reacted from the balanced equation = 5 x 32 = 160g

Now, we can obtain the mass of C2H2 that will react with 68.1g of O2 as follow:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, Xg of C2H2 will react with 68.1g of O2 i.e

Xg of C2H2 = (52x68.1)/160

Xg of C2H2 = 22.13g

Therefore, 22.13g of C2H2 is needed to react with 68.1g of O2

8 0
3 years ago
An ionic bond can be formed when one or more electrons are
xz_007 [3.2K]

Answer:

Are transferred completely from the valence shell of an element to the other

Explanation:

Basically, to form a chemical bond, you either transfer or you share. When you share, it is a case of covalent bonding which can be in several other forms. When there is a transfer, it is a case of ionic bonding.

The basic explanation for this is that while some atoms are electronically sufficient, some are electronically deficient. This means while some atoms are having an excess number of electrons, then some are having less number of electrons.

To satisfy both parties, there must be a transfer if electrons between the two parties. While the one with the excess numbers serves as the donor, the one with insufficient number of electrons serve as the acceptor

8 0
2 years ago
A voltaic cell is constructed using the following half-reactions: Ag+(aq) + e- ---> Ag(s) EoAg+ = +0.80 V Cu2+(aq) + 2e- ---&
Anton [14]
- Standard reduction potential of Ag/Ag⁺ is 0.80 v and that of Cu⁺²(aq)/Cu⁰ is +0.34 V.
- The couple with a greater value of standard reduction potential will oxidize the reduced form of the other couple.
Ag⁺ will be reduced to Ag(s) and Cu⁰ will be oxidized to Cu²⁺
Anode reaction: Cu⁰(s) →  Cu²⁺ + 2 e⁻     E⁰ = +0.34 V
Cathode reaction: Ag⁺(aq) + e → Ag(s)     E⁰ = +0.80 V 
Cell reaction: Cu⁰(s) + 2 Ag⁺(aq) → Cu⁺²(aq) + 2 Ag⁰(s)
E⁰ cell = E⁰ cathode + E⁰ anode
            = 0.80 + (-0.34) = + 0.46 V
   
5 0
3 years ago
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