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3 years ago

How molecules of N2 gas can be present in a 2.5 L flask at 50°C and 650 mmHg?

Chemistry

1 answer:

ratelena [41]3 years ago

5 0

Answer:

0.482 ×10²³ molecules

Explanation:

Given data:

Volume of gas = 2.5 L

Temperature of gas = 50°C (50+273 = 323 k)

Pressure of gas = 650 mmHg (650/760 =0.86 atm)

Molecules of N₂= ?

Solution:

PV= nRT

n = PV/RT

n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k

n = 2.15 atm. L /26.52 atm. mol⁻¹.L

n = 0.08 mol

Number of moles of N₂ are 0.08 mol.

Number of molecules:

one mole = 6.022 ×10²³ molecules

0.08×6.022 ×10²³ = 0.482 ×10²³ molecules

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When naming a binary compound, what ending do you use to represent anions?

spin [16.1K]

I believe You replace the ending of the elements name with -ide. example: magnesium flourine should should be magnesium flouride.

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3 years ago

The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-

grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

$2N_2O \rightarrow 2N_2 + O_2$

rate constant $k = 1.94\times 10^{-4} min^{-1}$

Half life $t_{1/2} = \frac{0.693}{k} = 3572 min$

Initial pressure $N_2 O = 4.70 atm$

Pressure after 3572 min = P

According to first order kinematics

$k = \frac{1}{t} ln\frac{4.70}{P}$

$1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}$

solving for P we get

P = 2.35 atm

$2N_2O \rightarrow 2N_2 + O_2$

initial 4.70 0 0

change -2x +2x +x

final 4.70 -2x 2x x

pressure of $O_2$ after first half life = 2.35 = 4.70 - 2x

x = 1.175

pressure of $N_2$ after first half life = 2x = 2(1.175) = 2.35 ATM

Total pressure = 2.35 + 2.35 + 1.175

= 5.875 atm

5 0

3 years ago

Read 2 more answers

A device which converts chemical energy into electric energy with brainliest

vampirchik [111]

battery

bro look it up first and do some searching and if you don't get a answer then ask it up here your just gonna waste your points

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3 years ago

A flask containing 855 grams of water was heated. If the temperature of the water was raised from 21.0 to 85.0 degrees Celsius,

marin [14]

Answer:

The heat absorbed by the water is 228,948.48 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

In this way, between heat and temperature there is a direct proportional relationship (Two magnitudes are directly proportional when there is a constant so that when one of the magnitudes increases, the other also decreases; and the same happens when either of the two decreases .). The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat and the mass of the body. So, the equation that allows to calculate heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

c= 4.184 $\frac{J}{g*C}$
m=855 g
ΔT= Tfinal - Tinitial= 85 °C - 21°C= 64 °C

Replacing:

Q= 4.184 $\frac{J}{g*C}$ *855 g* 64 C

Solving:

Q= 228,948.48 J

The heat absorbed by the water is 228,948.48 J

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3 years ago

What is the difference between an enthalpy driven reaction and entropy driven reaction?

Crazy boy [7]

Enthalpy is regarding the amount of heat that is given off or taken in during the process of a reaction, while entropy is about the disorderliness of a reaction.
Both are related in the equation ∆G=∆H-T∆S, where ∆G is the Gibbs free energy. So we can say that a reaction is both enthalpy and entropy driven. It's like, both of them are interlinked with each other.

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3 years ago