Answer:
The entropy decreases.
Explanation:
The change in the standard entropy of a reaction (ΔS°rxn) is related to the change in the number of gaseous moles (Δngas), where
Δngas = n(gaseous products) - n(gaseous reactants)
- If Δngas > 0, the entropy increases
- If Δngas < 0, the entropy decreases.
- If Δngas = 0, there is little or no change in the entropy.
Let's consider the following reaction.
2 H₂(g) + O₂(g) ⟶ 2 H₂O(l)
Δngas = 0 - 3 = -3, so the entropy decreases.
<h3>
Answer:</h3>
7.226 × 10^23 molecules.
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Explanation:</h3>
- A compound is a substance that is made by two or more atoms from different elements.
- A mole of a compound contains a number of molecules equivalent to Avogadro's number, 6.022 × 10^23.
- That is, one mole of a compound contains 6.022 × 10^23 molecules.
In this case we are given;
Number of moles of H₂O as 1.2 moles
But, 1 mole of H₂O contains 6.022 × 10^23 molecules.
We are required to calculate the number of molecules present;
- To calculate the number of molecules we are going to multiply the number of molecules in one mole by the number of moles.
Number of molecules = 1.2 moles × 6.022 × 10^23 molecules/mole
= 7.226 × 10^23 molecules.
Thus, 1.2 moles of water contains 7.226 × 10^23 molecules.
BH3 VSEPR. Boron trihydride structure, BH3. On B, there are three bonded domains and no lone pairs, which give molecular geometries and trigonal planar electron-domain.
