All categories

3 years ago

Pushing the body harder than it's ready to be pushed during exercise

1 answer:

5 0

Pushing the body harder than its ready to be pushed during exercise can lead to getting badly hurt. It can also help to increase the limit of the body power. It should be kept in mind that pushing the body to over the limits can be a very dangerous matter and this should only be done under the supervision of the experts.

You might be interested in

Which is an example of sliding friction?

stepan [7]

Answer:

You rubbing your hands together

Your hands are sliding against each other

5 0

3 years ago

The voltage in a battery is 9 volts. The resistance is 3 ohms. What is the current? USE CORRECT UNITS!

chubhunter [2.5K]

Answer: Lol “USE CORRECT UNITS!” I GOT YOU BABES: 9/3=3 current is 3 amperes.

Explanation:

3 0

3 years ago

A 50 W light bulb is plugged into a standard

wolverine [178]

Answer:

$1.26

Explanation:

Power =energy/ time

energy =powerxtime

energy =50x31x24=37200

=37.2kwh

1kwh =3.39

37.2kwh=3.39x37.2=126.108cent

=$1.26

8 0

3 years ago

Do action and reaction happen at the same time?

nikklg [1K]

the answer is Yes because your reaction will be an action

8 0

3 years ago

Read 2 more answers

harge of uniform density (100 nC/m3) is distributed throughout a hollow cylindrical region formed by two coaxial cylindrical sur

Elden [556K]

Answer:

The magnitude of the electric field is 8.47 N/C

Explanation:

Given;

uniform charge density, λ = 100 nC/m³

inner radii of the cylinder, r = 1.0 mm and 3.0 mm

distance from the symmetry axis, R = 2.0 mm

$Volume =\pi (R^2 -r^2)l\\\\Volume =\pi ((2*10^{-3})^2 -(1*10^{-3})^2)l\\\\Volume =\pi (4*10^{-6} - 1*10^{-6})l\\\\Volume = 3*10^{-6} \pi l \ m^3$

Area = 2πrl

Area =2π(2 x 10⁻)l

Volume = A x d

d = Volume / Area

$d = \frac{V}{A} = \frac{3*10^{-6}*\pi*l}{4\pi *10^{-3} l} = 75 *10^{-5} \ m$

the magnitude of the electric field

$E = \frac{\lambda *d}{\epsilon_o} = \frac{100*10^{-9} *75*10^{-5}}{8.854*10^{-12}} \\\\E = 8.47 \ N/C$

Therefore, the magnitude of the electric field is 8.47 N/C

6 0

3 years ago