What is 301.095 feet in expanded notation

Plz help cause idk what to do

mixer [17]

Answer:

-9.5 + 6x ≥ 42.1

6x ≥ 51.6

x ≥ 8.6

Here, we can see that x is greater than or equal to 8.6. So, we can say that 8.6 is the lowest value of x

but we have 2 options with 8.6 as the lowest term, we can see that the brackets are different in the beginning

the '[' bracket tells us to include 8.6 in the values of x whereas the '(' bracket tells to exclude 8.6 from the possible values of x

since we know that x is greater than or equal to 8.6, we will use the '[' bracket

Hence, b is your answer

PS: i need one brainly to reach the next rank, if you find this answer helpful. Mark Brainliest

8 0

4 years ago

Which function is shown in the graph?

muminat

Answer: The correct answer choice is B

Step-by-step explanation:

I graphed each function on the desmos calculator and answer choice B matched the graph.

6 0

3 years ago

Pls helpppppp anyoneeee

defon

Answer:

16

Step-by-step explanation:

7 0

3 years ago

100 point to the first correct answer

miss Akunina [59]

Answer:

X ~ B(n, p)

Given: X ~ B(2, 5/17)

⇒ n = 2

⇒ p = 5/17

Binomial distribution formula:

$\sf P(X = x) = nC_x (1-p)^{(n-x)}p^x$

As n = 2, calculate P(X = 0), P(X = 1) and P(X = 2):

$\sf P(X = 0) = 2C0 (\frac{12}{17})^{(2-0)}(\frac{5}{17})^0=\dfrac{144}{289}}$

$\sf P(X = 1) = 2C1 (\frac{12}{17})^{(2-1)}(\frac{5}{17})^1=\dfrac{120}{289}}$

$\sf P(X = 2) = 2C2 (\frac{12}{17})^{(2-2)}(\frac{5}{17})^2=\dfrac{25}{289}}$

**Probability Distribution Table attached**

5 0

3 years ago

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0

3 years ago