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2 years ago

On both the spring and fall equinoxes, the sun's rays are vertically overhead at the _______

1 answer:

5 0

It is overhead at the equator, it is because the sun ray’s will be moving vertically as this will be directed at the equator. It is because if it moves vertically, it will hit or overhead the equator and this usually happens in spring and fall.

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Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe

vodka [1.7K]

We will use formula for the orbital velocity of Venus, which is v = 35.02 km/s.
An average distance to the Sun ( In kilometers ) is:
R = 0.723 * 149,579,871 km= 108,150,260 km.
Than we will calculate the orbital period ( T ).
v = 2 π R / T
T = 2 π R / v
T = 2 * 3.14 * 108,150,260 km / 126,072 km/s
T = 5389.75 s ≈ <span>224.5 days
The orbital period of Venus is approximately 224.5 days.</span>

6 0

3 years ago

Mars moves in an elliptical orbit around the sun, and the mass of mars is much less than the mass of the sun. at the instant sho

Bess [88]

I believe the answer would be that the system potential energy will increase; while the Mar's angular momentum will remain the same.
Mars rotates on its axis, completing one revolution every 24.6 hours. The axis of mars is tilted at 25 degrees and 12 minutes relative to its orbital plane about the Sun. This produces seasons on the surfaces of Mars, similar to the seasons on Earth.

4 0

2 years ago

TRUE OR FALSE.

quester [9]

False, it would actually increase. Plants absorb carbon dioxide for photosynthesis

5 0

2 years ago

Three objects are dropped from the top of a building. The first is thrown straight down with a velocity v, the second is thrown

murzikaleks [220]

Answer:

Second ball

Explanation:

When a ball is thrown up with a certain velocity when the object reaches the same point from where it was thrown the velocity of the object becomes equal to the velocity with which the ball was thrown.

First ball

$v_g_1^2-u^2=2as\\\Rightarrow v_g_1=\sqrt{2as+u^2}\\\Rightarrow v_g_1=\sqrt{2as+v^2}$

Second ball

$v_g_2^2-u^2=2as\\\Rightarrow v_g_2=\sqrt{2as+u^2}\\\Rightarrow v_g_2=\sqrt{2as+4v^2}$

Third ball

$v_g_3^2-u^2=2as\\\Rightarrow v_g_3=\sqrt{2as+0^2}\\\Rightarrow v_g_3=\sqrt{2as}$

From the equations above it can be seen that the second ball will have the highest velocity when it hits the ground.

So, $v_g_3$

5 0

3 years ago

A parcel is traveling on a horizontal conveyer belt moving at 1 meter/second. At the end of the conveyor belt, the parcel lands

Igoryamba

Assume the acceleration due to gravity is approximately 9.8 m/s^2

In 1 second, it will fall

s = ut + at^2/2

u = initial vertical velocity = 0

a = 9.8

t = 1

s is the distance it falls

= 9.8/2 = 4.9 m

But the parcel has a horizontal velocity of 1 m/s so it will travel 1 m horizontally in 1 second.

The answer would be

1 metre, 4.9 metres.

6 0

2 years ago