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pentagon [3]
3 years ago
13

Davien and Jackson are headed to a beach that is 50km from school. At noon, Davien leaves his house that is 10 km closer to the

beach than the school is and moves at 40 km/h. Jackson starts from school at 12:30 P.M. And moves at 100 km/h. What time does Davien reach the beach? * Answer Format: Time
Physics
1 answer:
snow_tiger [21]3 years ago
5 0

Distance between Davien's school and beach, D = 50 km.

Also, Davian's house is 10 km closer to the beach than the school.

So, distance between Davien's house and beach, d = 40 km.

Speed of Davian, s = 40 km/h.

Now, time taken is given by :

t =\dfrac{Distance}{Speed}\\\\t=\dfrac{40}{40}=1\ hour

Therefore, Davien reach the beach at 1 : 30 P.M .

Hence, this is the required solution.

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A 0.20 kg mass attached to the end of a spring causes it to stretch 3.0 cm. What is the spring constant? What is the potential e
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The spring constant can be calculated by the formula

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The maximum height to which the ball attain before falling back down is 1147.96 m

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Initial velocity (u) = 150 m/s
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The maximum height reached by the ball can be obtained as illustrated below:

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Divide both side by –19.6

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Thus, the maximum height reached by the ball is 1147.96 m

Learn more about motion under gravity:

brainly.com/question/22719691

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This question appear incomplete

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