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3 years ago

True or False: Waves become stronger as they travel away from their source

Physics

2 answers:

julia-pushkina [17]3 years ago

5 0

Answer:

False

Explanation:

They become weaker as they travel away from their source.

zmey [24]3 years ago

5 0

Answer : false

Explanation:

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A 50 kg bobsled slides down an ice track starting (at zero initial speed) from the top of a(n) 184 m high hill. The acceleration

Feliz [49]

Answer:

Explanation:

Given

mass of ice $m=50\ kg$

Height of hill $h=184\ m$

Neglecting air resistance

As resistance is absent so Energy at top of hill and at the bottom hill is conserved.

Energy at top is equal to Potential Energy

$E_T=mgh=50\times 9.8\times 184$

Energy at bottom is equal to kinetic energy at bottom

$E_B=\frac{1}{2}mv^2$

$E_T=E_B$

$50\times 9.8\times 184=\frac{1}{2}\times 50\times v^2$

$v=\sqrt{2\times 9.8\times 184}$

$v=60.05\ m/s$

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4 years ago

What is total mechanical energy?

ollegr [7]

Answer:

is the energy possessed by an object due to either its motion or its stored energy of position. The total amount of mechanical energy is merely the sum of these two forms of energy. And finally, an object with mechanical energy is able to do work on another object.

Explanation:

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3 years ago

what will be the speed of a solid sphere of mass 2.0 kilograms and radius 15.0 centimeters when it reaches the bottom of a incli

Yuki888 [10]

Explanation:

Below is an attachment containing the solution.

4 0

4 years ago

A 0.140 kg stone rests on a frictionless, horizontal surface. A bullet of mass 8.50 g , traveling horizontally at 320 m/s , stri

Novay_Z [31]

Answer:

a) $v = 34.607\,\frac{m}{s}$ (Positive), b) $e = 0.803$ . The collision is not perfectly elastic.

Explanation:

a) The collision can be described by the Principle of Momentum Conservation and Principle of Energy Conservation:

$(0.140\,kg)\cdot (0\,\frac{m}{s} ) + (0.0085\,kg)\cdot (320\,\frac{m}{s} ) = (0.0085\,kg)\cdot (-250\,\frac{m}{s} ) + (0.140\,kg)\cdot v$

The final velocity of the rock is:

$v = 34.607\,\frac{m}{s}$

b) The coefficient of restitution is the best criterion to distinguish elastic collsions from inelastic collisions, such criterion is the ratio of final energy of the system to initial energy of the system:

$e = \frac{\frac{1}{2}\cdot [(0.140\,kg)\cdot (34.607\,\frac{m}{s} )^{2}+(0.0085\,kg)\cdot (-250\,\frac{m}{s} )^{2}] }{\frac{1}{2}\cdot [(0.140\,kg)\cdot (0\,\frac{m}{s} )^{2}+(0.0085\,kg)\cdot (320\,\frac{m}{s} )^{2}] }$