<span>Nitrogen-14 should be the correct response.</span>
To simplify our solution for this probelm we first assume that the gas we are dealing with is an ideal gas. Given that it is ideal we can proceed the solution using the formula: PV=nRT where P is pressure (203KPa), V is volume (20.0 L), n is moles (required), T is absolute temperature (373K) and R is the gas constant ( <span>8.31 l-kpa/m-k). Plug in the given to the respective variables and you should get 3.28 moles of the gas sample. </span>
Answer:
Therefore, none of the zeros is a significant figure and hence there is only one significant figure in this measurement in support G. The measurement is 0.7 minutes. Here again, zero is not a significant figure and therefore the only significant figure is one which is seven in support Edge.
Explanation:
Condensation is your answer!
<span>SO3
for the formal charges, we have:
for the single-bonded oxygens F.C. = 6 - [1/2(2) + 6] = -1
for the double-bonded oxygen F.C. = 6 - [1/2(4) + 4] = 0
for the sulfur F.C. = 6 - [1/2(8) + 0] = 2
Again, the formal charges add to zero. The oxidation numbers of O and S are -2 and +6, respectively. Note the three resonance forms!</span>
