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astraxan [27]
3 years ago
11

If a certain gas occupies a volume of 19 L when the applied pressure is 9.5 atm, find the pressure when the gas occupies a volum

e of 4.8 L
Chemistry
1 answer:
kakasveta [241]3 years ago
3 0

Answer: 37.6 atm

Explanation:

Given that,

Initial volume of gas (V1) = 19L

Initial pressure of gas (P1) = 9.5 atm

Final volume of gas (V2) = 4.8L

Final pressure of gas (P2) = ?

Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law

P1V1 = P2V2

9.5 atm x 19L = P2 x 4.8L

180.5 atm•L = 4.8L•P2

Divide both sides by 4.8L

180.5 atm•L/4.8L = 4.8L•P2/4.8L

37.6 atm = P2

Thus, the final pressure is 37.6 atmospheres.

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The density of the rectangular block in g/mL is 7.0.

<u>Given the following data:</u>

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  • Width of block = 5.83 cm
  • Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

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<u>Conversion:</u>

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Cross-multiplying, we have:

X = 2.54(5.83)\\\\X = 14.81 \; cm

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Cross-multiplying, we have:

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