Answer:
the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
Explanation:
We will use Bernoulli's theorem in order to determine the pressure lift:
ΔP = 1/2 (ρ)(v₂² - v₁²)
the generated pressure lift is ΔP = 1000 N/m²
Therefore,
1000 = 1/2(ρ)(v₂² - v₁²)
v₂² - v₁² = 2000 / ρ
v₂² = (2000 N/m² / 1.29 kg/m³) + (62 m/s)²
v₂ = √[ (2000 N/m² / 1.29 kg/m³) + (62 m/s)² ]
<em>v₂ = 73.4 m/s </em>
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Therefore, the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
Answer:
x = 0.176 m
Explanation:
For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.
Let's use trigonometry to decompose the tension
sin 60 =
/ T
T_{y} = T sin 60
cos 60 = Tₓ / T
Tₓ = T cos 60
we apply the equation
∑ τ = 0
-W L / 2 - w x + T_{y} L = 0
the length of the bar is L = 6m
-Mg 6/2 - m g x + T sin 60 6 = 0
x = (6 T sin 60 - 3 M g) / mg
let's calculate
let's use the maximum tension that resists the cable T = 900 N
x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)
x = (4676 - 5880) / 6860
x = - 0.176 m
Therefore the block can be up to 0.176m to keep the system in balance.
Gravitational force is given by, 
Where, m and M are the masses of the objects, R is the distance between them and G gravitational constant.
Gravitational force of the star on planet 1, 
Gravitational force of the star on planet 2, 
Ratio, 

Therefore, the gravitational force of the star on the planet 1 is three times that on planet 2.
Answer:
42.87
Explanation:
Google
<u>OR</u>
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420/9.8 which equals 42.87.
Answer:
0.31 m
Explanation:
m = mass of the block = 1.5 kg
H = height from which the block is released on ramp = 0.81 m
k = spring constant of the spring = 250 N/m
x = maximum compression of the spring
using conservation of energy
Spring potential energy gained by spring = Potential energy lost by block
(0.5) k x² = mgH
(0.5) (250) x² = (1.5) (9.8) (0.81)
x = 0.31 m